PbCrO4, which is lead(II) chromate, is a solid under normal conditions. The compound is ionic in nature, consisting of a +2 lead cation and a -2 chromate anion. Ionic compounds are nearly all crystalline solids at room temperature.
Lead(II) iodide (PbI2) is typically a yellow colored solid.
Formula: PbI2
The oxidation number of lead (Pb) in PbI2 is +2. Iodine (I) typically has an oxidation number of -1 in compounds. Since there are two iodine atoms in PbI2, the total negative charge contributed by iodine is -2. This balances with the +2 charge of lead to make PbI2 neutral.
Pb(NO3)2(aq) + 2KI)aq) = 2KNO3(aq)+ PbI2(s) PbI2 is a yellow coloured solid and will precipitate out of the solution.
The balanced equation for lead iodide is: PbI2 (s) ↔ Pb2+ (aq) + 2I- (aq)
Lead(II) iodide (PbI2) is typically a yellow colored solid.
Formula: PbI2
The oxidation number of lead (Pb) in PbI2 is +2. Iodine (I) typically has an oxidation number of -1 in compounds. Since there are two iodine atoms in PbI2, the total negative charge contributed by iodine is -2. This balances with the +2 charge of lead to make PbI2 neutral.
Pb(NO3)2(aq) + 2KI)aq) = 2KNO3(aq)+ PbI2(s) PbI2 is a yellow coloured solid and will precipitate out of the solution.
The balanced equation for lead iodide is: PbI2 (s) ↔ Pb2+ (aq) + 2I- (aq)
Formula: PbI2
PbI2
Pb(No3)2(aq) + KI(aq) --> PbI2(s) + KNO3(aq) aq = aqueous s = solid Lead iodide is a yellow precipitate!
It would be: PbI2
Formula: PbI2
Formula: PbI2
This is a solid.