PBI2, or lead(II) iodide, consists of one lead (Pb) atom and two iodine (I) atoms. Therefore, there are a total of three atoms in one formula unit of PBI2.
This is a solid.
Yes, lead iodide (PbI2) is a naturally occurring mineral known as iodargyrite. It is a rare mineral found in some mineral deposits, but it is more commonly synthesized for various industrial applications.
Formula: PbI2
Five atoms
The spectator ions in this precipitation equation are K+ and NO3-. The non-spectator ions are Pb2+ and I-. They combine to form the precipitate PbI2.
There are three elements in PbI2: lead (Pb), iodine (I), and two iodine atoms bonded to the lead atom.
The answer depends on the amount of the substance.
PbI2 has TWO(2) elements. They are ;- Pb ; Lead (Plumbum ; Latin) I ; Iodine . However, there are three (3) atoms in PbI2. Viz: - 1 x Pb(Lead) 2 x I (iodine) 1 + 2 = 3 The name of the sibstance is 'lead iodide'.
The oxidation number of lead (Pb) in PbI2 is +2. Iodine (I) typically has an oxidation number of -1 in compounds. Since there are two iodine atoms in PbI2, the total negative charge contributed by iodine is -2. This balances with the +2 charge of lead to make PbI2 neutral.
Two: lead and iodine.
Lead(II) iodide (PbI2) is typically a yellow colored solid.
Formula: PbI2
The chemical formula for lead (II) iodide is PbI2. It is composed of one lead (Pb) atom and two iodine (I) atoms.
Pb(NO3)2(aq) + 2KI)aq) = 2KNO3(aq)+ PbI2(s) PbI2 is a yellow coloured solid and will precipitate out of the solution.
The balanced equation for lead iodide is: PbI2 (s) ↔ Pb2+ (aq) + 2I- (aq)
Formula: PbI2
PbI2