PbI2 has TWO(2) elements.
They are ;-
Pb ; Lead (Plumbum ; Latin)
I ; Iodine .
However, there are three (3) atoms in PbI2. Viz: -
1 x Pb(Lead)
2 x I (iodine)
1 + 2 = 3
The name of the sibstance is 'lead iodide'.
There are three elements in PbI2: lead (Pb), iodine (I), and two iodine atoms bonded to the lead atom.
Lead(II) iodide (PbI2) is typically a yellow colored solid.
Formula: PbI2
The oxidation number of lead (Pb) in PbI2 is +2. Iodine (I) typically has an oxidation number of -1 in compounds. Since there are two iodine atoms in PbI2, the total negative charge contributed by iodine is -2. This balances with the +2 charge of lead to make PbI2 neutral.
Pb(NO3)2(aq) + 2KI)aq) = 2KNO3(aq)+ PbI2(s) PbI2 is a yellow coloured solid and will precipitate out of the solution.
There are three elements in PbI2: lead (Pb), iodine (I), and two iodine atoms bonded to the lead atom.
Two: lead and iodine.
Lead(II) iodide (PbI2) is typically a yellow colored solid.
Formula: PbI2
The oxidation number of lead (Pb) in PbI2 is +2. Iodine (I) typically has an oxidation number of -1 in compounds. Since there are two iodine atoms in PbI2, the total negative charge contributed by iodine is -2. This balances with the +2 charge of lead to make PbI2 neutral.
Pb(NO3)2(aq) + 2KI)aq) = 2KNO3(aq)+ PbI2(s) PbI2 is a yellow coloured solid and will precipitate out of the solution.
The balanced equation for lead iodide is: PbI2 (s) ↔ Pb2+ (aq) + 2I- (aq)
Formula: PbI2
PbI2
It would be: PbI2
Formula: PbI2
Formula: PbI2