These ions are Pb(2+) and I-.
Potassium iodide and lead nitrate produces lead iodide and potassium nitrate its a Precipitation Reactions. 2KI+Pb(NO3)2-->PbI2 + 2KNO3
The molecular equation for the reaction between potassium carbonate (K2CO3) and strontium nitrate (Sr(NO3)2) is: 2K2CO3 + Sr(NO3)2 → 2KNO3 + SrCO3
Potassium Nitrite
Potassium chloride and magnesium nitrate doesn't react.
K2CO3 + 2HNO3 = 2KNO3 (potassium nitrate) + H2O + CO2 and it's nitric acid
Potassium iodide and lead nitrate produces lead iodide and potassium nitrate its a Precipitation Reactions. 2KI+Pb(NO3)2-->PbI2 + 2KNO3
No, the given chemical equation is not balanced. The balanced equation is: 2K2CrO4(aq) + Pb(NO3)2(aq) → 2KNO3(aq) + PbCrO4(s)
Pb(NO3)2 + 2KCl ---> PbCl2 + 2KNO3
To balance the equation Pb(NO3)2 + 2KI → PbI2 + 2KNO3, you need to ensure that the number of each type of atom is equal on both sides of the equation. In this case, you need to add coefficients in front of the compounds to achieve this balance.
Pb(No3)2(aq) + KI(aq) --> PbI2(s) + KNO3(aq) aq = aqueous s = solid Lead iodide is a yellow precipitate!
Pb(NO3)2(aq) + 2KI)aq) = 2KNO3(aq)+ PbI2(s) PbI2 is a yellow coloured solid and will precipitate out of the solution.
The balanced chemical equation for the reaction between barium nitrate (Ba(NO3)2) and potassium hydroxide (KOH) is: Ba(NO3)2 + 2KOH -> Ba(OH)2 + 2KNO3
Pb(NO3)2 + 2KI -> PbI2 + 2KNO3.
2 KNO3 ↔ 2 KNO2 + O2
The molecular equation for the reaction between potassium carbonate (K2CO3) and strontium nitrate (Sr(NO3)2) is: 2K2CO3 + Sr(NO3)2 → 2KNO3 + SrCO3
Pb(NO3)2 + 2KI ==> PbI2 + 2KNO3 is a precipitation reaction. The PbI2 is insoluble in water and will precipitate. It is NOT neutralization, because you do not have an acid reacting with a base.
The balanced chemical equation for this reaction is: 2KBr + Al(NO3)3 → 2KNO3 + AlBr3