My guess is Fe2+ as FeSCN3+ is light red at least. Not sure, but I guess you'd use the HCL for oxidizing the iron to Fe3+
3.56 g 3 AgNO3 + AlCl3 --> 3 AgCl + Al(NO3)3 AgCl3 is the limiting reagent (I checked), so: 4.22 g AgNO3 * (1 mol AgNO3/169.88 g AgNO3) * (3 mol AgNO3/3 mol AgCl3) * (143.32 mol AgCl3/1 mol AgCl3) =3.56 g AgCl3See the Related Questions to the left for more information about solving stoichiometry problems of this nature.
The Limiting Reactant is the reactant that runs out first in a reaction.
To determine the limiting reactant, we need to compare the moles of each reactant to the stoichiometry of the reaction. The balanced equation is needed for this calculation. From the balanced equation, we can see the molar ratio between Al and AgNO3. Whichever reactant is present in a lower amount relative to this ratio will be the limiting reactant.
When a substance/ solution containing chlorine ions is added with acidified silver nitrate (i.e. adding nitric acid to silver nitrate first), a yellow, insoluble ppt in formed.
Baking soda
3.56 g 3 AgNO3 + AlCl3 --> 3 AgCl + Al(NO3)3 AgCl3 is the limiting reagent (I checked), so: 4.22 g AgNO3 * (1 mol AgNO3/169.88 g AgNO3) * (3 mol AgNO3/3 mol AgCl3) * (143.32 mol AgCl3/1 mol AgCl3) =3.56 g AgCl3See the Related Questions to the left for more information about solving stoichiometry problems of this nature.
The Limiting Reactant is the reactant that runs out first in a reaction.
The Limiting Reactant is the reactant that runs out first in a reaction.
To find how many grams of silver nitrate can be produced, first determine the limiting reactant. Calculate the moles of silver nitrate and calcium chloride in the given volumes and concentrations. The reactant that produces fewer moles of silver nitrate will be the limiting reactant. Then use stoichiometry to find the amount of silver nitrate that can be produced from the limiting reactant.
To determine the limiting reactant, we need to compare the moles of each reactant to the stoichiometry of the reaction. The balanced equation is needed for this calculation. From the balanced equation, we can see the molar ratio between Al and AgNO3. Whichever reactant is present in a lower amount relative to this ratio will be the limiting reactant.
The Limiting Reactant is the reactant that runs out first in a reaction.
The reaction is first order with respect to the reactant. In a first-order reaction, the rate is directly proportional to the concentration of the reactant. Doubling the concentration of a reactant will result in a doubling of the reaction rate.
When a substance/ solution containing chlorine ions is added with acidified silver nitrate (i.e. adding nitric acid to silver nitrate first), a yellow, insoluble ppt in formed.
Baking soda
Balanced equation first! AgNO3 + NaCl -> AgCl + NaNO3 all one to one, get moles AgNO3 3.82 moles NaCl (1 mole AgNO3/1 mole NaCl) = 3.82 moles AgNO3 ------------------------------- Molarity = moles of solute/Liters of solution 0.117 M AgNO3 = 3.82 moles AgNO3/Liters Liters = 3.82/0.117 = 32.6 Liters which is 32600 milliliters which is unreasonable; check answer if you can
AgBr + KNO3 In most chemical reactions, The first part of the first compound (Ag) combines with the second part of the second compound (Br). And then the first part of the second compound (K), combines with the second part of the first compound (NO3). Also, the 3 at the end of NO3 should be in subtext. If all that makes sense.
To find the mass of AgBr formed, first calculate the moles of AgNO3 in 35.5 mL of 0.184 M solution. Then, use the mole ratio from the balanced chemical equation between AgNO3 and AgBr to find the moles of AgBr formed. Finally, multiply the moles of AgBr by its molar mass to get the mass. Note that since HBr is in excess, AgNO3 will be the limiting reagent.