They both react with phenol. KOH is actually a slightly stronger base than NaOH.
At low concentrations, like less than 0.1M, both NaOH and KOH are essentially 100% dissociated. However, at higher concentrations, a little more of the KOH is dissociated. The point is, both bases will remove virtually all of the H+ from phenol. You received some incorrect information.
Phenol is acidic in nature. The phenolate anion is stable through resonance. Hence, an acid base reaction ensues between phenol and NaOH in water resulting in the formation of sodium phenolate, which is highly soluble in water compared to phenol.
Sodium phenoxide is the sodium salt of phenol. It is formed when sodium hydroxide (NaOH) reacts with phenol (C6H5OH) in a neutralization reaction. Sodium phenoxide is commonly used in organic synthesis as a strong base.
In the presence of aqueous NaOH, phenol undergoes nucleophilic aromatic substitution reaction to form sodium phenoxide. When CCl4 is added, no reaction occurs as CCl4 is non-reactive towards phenoxide ion.
The balanced equation for the reaction between phenol (C6H5OH), sodium hydroxide (NaOH), and iron(III) chloride (FeCl3) is: C6H5OH + NaOH + FeCl3 → C6H4(OH)Na + FeCl2 + H2O
The chemical reaction is:Na2Cr2O7 + 2 NaOH = 2 Na2CrO4 + H2O
Phenol is not dissolved in a sodium hydroxide solution; having the characteristics of a weak acid phenol react with NaOH.
Phenol is acidic in nature. The phenolate anion is stable through resonance. Hence, an acid base reaction ensues between phenol and NaOH in water resulting in the formation of sodium phenolate, which is highly soluble in water compared to phenol.
Sodium phenoxide is the sodium salt of phenol. It is formed when sodium hydroxide (NaOH) reacts with phenol (C6H5OH) in a neutralization reaction. Sodium phenoxide is commonly used in organic synthesis as a strong base.
Phenol is a strong acid so it may be neutralized by any base as NaOH
Alcohol: C6H13OH (hydroxy-hexane) Phenol : C6H5OH (hydroxy-benzene) Phenolic -OH is acidic (4x stronger than vinegar) where s alcoholic -OH isn't acidic at all; both are NOT ionic or alkaline (OH-)
In the Reimer-Tiemann reaction, the electrophile is the carbene (CHCl3) that forms from the reaction of phenol with CCl4 in the presence of a base such as NaOH. This carbene then reacts with phenol to form the trichloromethane derivative. The mechanism involves the generation of the carbene intermediate, which attacks the phenol molecule to form the final product.
In the presence of aqueous NaOH, phenol undergoes nucleophilic aromatic substitution reaction to form sodium phenoxide. When CCl4 is added, no reaction occurs as CCl4 is non-reactive towards phenoxide ion.
The balanced equation for the reaction between phenol (C6H5OH), sodium hydroxide (NaOH), and iron(III) chloride (FeCl3) is: C6H5OH + NaOH + FeCl3 → C6H4(OH)Na + FeCl2 + H2O
The chemical reaction is:Na2Cr2O7 + 2 NaOH = 2 Na2CrO4 + H2O
When sulfuric acid (H2SO4) reacts with sodium hydroxide (NaOH), the salt produced is sodium sulfate (Na2SO4) along with water.
NaOH is formed then. NaOH is a strong base.
Yes, benzoic acid is soluble in NaOH because when it reacts with NaOH, it forms the water-soluble salt sodium benzoate.