If this is the outcome of a (too) simplified calculation formula for pH of hydroxide solutions, then here is the 'missing' part to correct this 'false' answer (or outcome):
pH = 14.0 - pOH = 14.0 - [-log(OH-)] (this is generally valid at room temperature 25oC)
so by adding the amount of OH- ions, already present in pure water. This can NOT longer be ignored when NaOH concentration is very diluted, below 10-6 mol/L.
So when pHoutcome < 8 for dilute bases it should be 'recalculated' by addition of 10-7 before taking any log !
(The same is analogously valid for dilute acids when pHoutcome > 6)
pHoutcome = 6 for this NaOH concentration (which appears to have been (NaOH) = 1.0*10-8) is lower than 8 so is to be corrected as follows:
pH = 14.0 + log[(NaOH) + (1.0*10-7)] = 14 + log[1.0*10-8 + 1.0*10-7] =
= 14 + log[1.1*10-7] = 14 - 6.96 = 7.04 = 7.0
(and not 6 as in the simplified formula outcome)
The pH of a 1.0 x 10^-6 M NaOH solution is approximately 11.00. This is because NaOH is a strong base that dissociates completely in solution to produce hydroxide ions, resulting in a high pH.
6N NaOH refers to a solution of sodium hydroxide (NaOH) that has a concentration of 6 normal (6N) strength. This means that the solution contains a high concentration of NaOH, which is a strong base commonly used in laboratory settings for various chemical reactions.
MW NaOH is 23+16+1 = 40. 4.5g in 750ml is 6.0g in 1L. Molarity is 6/40 = 0.15 OH- concentration is 0.15, pOH is -log100.15 = 0.82 H+ concentration is 10-14/0.15 = 6.67x10-13 pH is -log10 6.67x10-13 = 12.18
yes. 1-6 is acid 7 is neutral and 8-14 is base so 11 is base.
Anything with a pH less than 7 is an acid. Anything with a pH greater than 7 is a base. pH = 7 is neutral
The pH of a 1.0 x 10^-6 M NaOH solution is approximately 11.00. This is because NaOH is a strong base that dissociates completely in solution to produce hydroxide ions, resulting in a high pH.
6N NaOH refers to a solution of sodium hydroxide (NaOH) that has a concentration of 6 normal (6N) strength. This means that the solution contains a high concentration of NaOH, which is a strong base commonly used in laboratory settings for various chemical reactions.
Bases have a pH > 7.0 BUT this merely describes the concentration of ions. Strong usually describes if all the substance ionizes, not how many ions are present. EX. NaOH is a strong base, but the pH of a solution of NaOH can be anywhere from 7.1 to 14 depending on how much has been dissolved.
A base is anywhere from 8 to 14 on the Ph scale. If a base of about 8 is added to and acid of about 6, the Ph will be balanced out.
MW NaOH is 23+16+1 = 40. 4.5g in 750ml is 6.0g in 1L. Molarity is 6/40 = 0.15 OH- concentration is 0.15, pOH is -log100.15 = 0.82 H+ concentration is 10-14/0.15 = 6.67x10-13 pH is -log10 6.67x10-13 = 12.18
An acid is 0-6 on the pH scale. Neutral is around a 7. Around 8 and above is the pH for a base.
To calculate the pH after each volume of NaOH is added, you need to determine the moles of HBr initially, moles of NaOH added, and then use these values to calculate the final concentration of H3O+ ions in the solution. From there, you can calculate the pH using the equation pH = -log[H3O+]. Repeat these calculations for each volume of NaOH added to find the pH at 12.5 ml, 18.7 ml, 20.0 ml, 29.5 ml, and 34.2 ml.
yes. 1-6 is acid 7 is neutral and 8-14 is base so 11 is base.
Anything with a pH less than 7 is an acid. Anything with a pH greater than 7 is a base. pH = 7 is neutral
To prepare a 6N NaOH solution, you would need to dissolve 240 grams of sodium hydroxide (NaOH) pellets in enough distilled water to make 1 liter of solution. This will result in a 6N (Normal) solution of NaOH. Remember to handle NaOH with caution as it is a strong base and can cause burns.
Coffee is a mild base around 6 pH (water has a pH of 7).
A solution with a pH of 6 is considered acidic. pH values below 7 indicate acidity, while pH values above 7 indicate alkalinity.