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What is the molarity of 2.5 mol KCI in 1.0 L of solution?
You want to get the concentration that would be in a litre. for every 750ml, there is 1 mol. so 1/750, x1000 will give you 1.333 molar. i.e. 1.333 moles in every litre.
What is the molarity of 750 mL of NaCl solution that contains 21.04 g of NaCl?
To calculate the molarity of the NaCl solution, first convert the mass of NaCl to moles using its molar mass. The molar mass of NaCl is 58.44 g/mol. Then, divide the moles of NaCl by the volume of the solution in liters (750 mL = 0.75 L) to get the molarity. In this case, the molarity of the NaCl solution is 1.5 M.
What is the molarity of a solution prepared by dissolving 175 g of KNO3 in 750mL of water?
Divide 175 by 750 and multiply by 1000 to get g/l. This gives you 233.3333g/litre. The molecular weight for KNO3 is 101.1g/mol. 233.333/101.1 is 2.31 molar.
How on earth do you find the molarity of a 750 ml solution containing 346g of potassium nitrate?
Well potassium nitrate has a molecular weight of 101. If there are 346g in 750ml there will be 346 x 1000/750 = 461.334 g in 1 liter. The solution is thus 461.334/101 = 4.57 molar (2 decimal places).
What volume of 0.10 m naoh can be prepared from 250 ml of 0.30 m naoh?
10.0 ml of a solution of 6.0 molar NaOH contains (10.0/1000)(6.0) = 0.060 moles of NaOH. Call the number of milliliters needed to make a solution that is 0.30 molar with this amount of NaOH v. Then 0.060/v = 0.30, or v = 50 ml. Ideally, this solution should be made by putting the 6.0 molar solution into a volumetric container calibrated to 50 ml, then diluting with water to the mark for 50 ml. As an approximation, 50 - 10.0 = 40 ml of water can be added, but this may not give an exact match because 6.0 molar NaOH solution probably has a density considerably higher than 1.00 grams/ml, the density of water at standard temperature and pressure, while the density of 0.30 molar solution is substantially less but may still not be as low as 1.00. Therefore, adding a specified volume of water may not result in a total volume equal to the sum of the volume of water added plus the 10.0 ml originally specified.
How many grams of NaOH are in 750 ml 0.600 M NaOH solution?
This solution contain 26,3 g NaOH.
What is the molarity of 2.5 mol KCI in 1.0 L of solution?
You want to get the concentration that would be in a litre. for every 750ml, there is 1 mol. so 1/750, x1000 will give you 1.333 molar. i.e. 1.333 moles in every litre.
What amount of solid naoh must be added to 750 g of an aqueous solution to make 2.5 percent NAOH solution by mass?
75gm
What is the molarity of 750 mL of NaCl solution that contains 21.04 g of NaCl?
To calculate the molarity of the NaCl solution, first convert the mass of NaCl to moles using its molar mass. The molar mass of NaCl is 58.44 g/mol. Then, divide the moles of NaCl by the volume of the solution in liters (750 mL = 0.75 L) to get the molarity. In this case, the molarity of the NaCl solution is 1.5 M.
What is the molarity of a solution prepared by dissolving 175 g of KNO3 in 750mL of water?
Divide 175 by 750 and multiply by 1000 to get g/l. This gives you 233.3333g/litre. The molecular weight for KNO3 is 101.1g/mol. 233.333/101.1 is 2.31 molar.
How on earth do you find the molarity of a 750 ml solution containing 346g of potassium nitrate?
Well potassium nitrate has a molecular weight of 101. If there are 346g in 750ml there will be 346 x 1000/750 = 461.334 g in 1 liter. The solution is thus 461.334/101 = 4.57 molar (2 decimal places).
What weight of NaOH should be dissolved in water to give 750 ml of a 0.35 M solution?
2gendpoint3.6 g
A solution contains 85.0 g of NaNO3 and has a volume os 750 mL find the molarity of the solution?
First, convert the mass of NaNO3 to moles using the molar mass of NaNO3. Then, calculate the molarity by dividing the moles of NaNO3 by the volume of the solution in liters. Molarity (M) = moles of solute / volume of solution in liters.
What volume of 0.10 m naoh can be prepared from 250 ml of 0.30 m naoh?
10.0 ml of a solution of 6.0 molar NaOH contains (10.0/1000)(6.0) = 0.060 moles of NaOH. Call the number of milliliters needed to make a solution that is 0.30 molar with this amount of NaOH v. Then 0.060/v = 0.30, or v = 50 ml. Ideally, this solution should be made by putting the 6.0 molar solution into a volumetric container calibrated to 50 ml, then diluting with water to the mark for 50 ml. As an approximation, 50 - 10.0 = 40 ml of water can be added, but this may not give an exact match because 6.0 molar NaOH solution probably has a density considerably higher than 1.00 grams/ml, the density of water at standard temperature and pressure, while the density of 0.30 molar solution is substantially less but may still not be as low as 1.00. Therefore, adding a specified volume of water may not result in a total volume equal to the sum of the volume of water added plus the 10.0 ml originally specified.
What is the molarity of CaBr2 if 1.50 mol makes 750.0 ml of solution?
You need to make this value in a litre. The sum is 1.5/750*100. This gives you a 2 molar solution.
How many grams of potassium chloride is contained in 750 ml of 1.25 M KCl solution?
we know that, molarity=(given mass/molar mass)*(1000/volume of solution in ml) all the dats are given,only we have to find out the given mass or the present mass of the KCl. 1.25=(given mass/74.5)*(1000/750) => given mass=(1.25*750*74.5)/1000 =69.84g.
How many moles of potassium iodide are needed to make 750 ml of a 1.8 M solution?
To find the number of moles of potassium iodide needed, multiply the volume of the solution (750 ml) by the molarity (1.8 moles/L). First, convert the volume to liters (750 ml = 0.75 L), then multiply 0.75 L by 1.8 moles/L to get 1.35 moles of potassium iodide.
