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0.0255 mol potassium hydroxide was dissolved in water to yield 10.0 mL of solution what is the molarity of the solution?
Molarity = Moles/Unit VolumeSo here Molarity = (0.0255) / (10-2) = 2.55 M
What is the molartiy of 0.5 liters of a solution with five moles of sucorse in it?
Molarity = moles of solute/Liters of solution Molarity = 5 moles sucrose/0.5 Liters = 10 M ----------
What is the molarity of 10 moles of salt dissolved in 20 liters of water?
The molarity of the salt solution can be calculated by dividing the number of moles of solute (salt) by the volume of solution in liters. In this case, the molarity would be 10 moles / 20 liters = 0.5 moles per liter (M).
What is the molarity of a solution made by dissolving 2 moles of NaOH in 10 kg of water?
The molarity of the solution would be approximately 0.2 M. This is calculated by first converting the mass of water to volume (10 kg is roughly equivalent to 10 L), then using the formula Molarity = moles of solute / volume of solution in liters.
What is the molarity of a 2.50 x 102 cm3 solution containing 45.0 g of C6H12O6?
Molarity is defined as moles solute/liter of solution.Moles of solute = 2.5 moles sucrose Liters of solution = 0.5 liters Molarity (M) = 2.5 moles/0.5 liters = 5 M
What would you be need to do to calculate the molarity of 10 mol of NaCl in 200?
To calculate the molarity of a solution, you would need to divide the number of moles of solute (in this case, 10 mol of NaCl) by the volume of solution in liters (in this case, 200 L). Molarity = moles of solute / liters of solution So, Molarity = 10 mol / 200 L = 0.05 M.
0.0255 mol potassium hydroxide was dissolved in water to yield 10.0 mL of solution what is the molarity of the solution?
Molarity = Moles/Unit VolumeSo here Molarity = (0.0255) / (10-2) = 2.55 M
What is the molarity of the solution containing 5.0 moles of KCl in 2.0 L of solution?
Molarity is moles per litre. So you have to convert volume to a litre. i.e. 0.5x2 is a litre. so you have to do the same to moles. 5x2 is 10 moles. as this is per litre, it is a 10 molar solution.
What is the molarity of 0.96 g MgCl2 in 0.500 L of solution?
To find the molarity, first calculate the moles of MgCl2 using its molar mass. Molar mass of MgCl2 = 95.21 g/mol Moles of MgCl2 = 0.96 g / 95.21 g/mol = 0.0101 mol Then, divide the moles by the volume in liters to find molarity: Molarity = 0.0101 mol / 0.500 L = 0.0202 M.
What will be the molarity for a solution prepared by dissolving a 10 grams compound with a molecular mass of 100 in 1 L of water?
The first step is to calculate the number of moles of the compound using the formula: moles = mass / molar mass. In this case, moles = 10 g / 100 g/mol = 0.1 moles. The molarity is then calculated by dividing the number of moles by the volume of solution in liters, so the molarity is 0.1 moles / 1 L = 0.1 M.
Calculate the molarity of a solution of potassium permanganate and density is 1.04 gmL which contans 15.00 percent by mass?
C [mol/L] = w% * rho [g/mL] *1000 [mL/L] / (100% * M [g/mol] ) = = w% * rho [g/mL] *10 [mL/L%] / ( M [g/mol] ) = = 15.00 % * 1.04 [g/mL] *10 [mL/L%] / ( 158.034 [g/mol] ) = = 0.987 [mol/L] the molarity of the solution of potassium [in mol per liter] equals the content of KMnO4 by mass in percents multiply by density in g/mL multiply by 10 [mL/(L*%)] divide by molar mass of KMnO4 (M = 158.034 g/mol) This gives 0.987 mol/L. Thus the molarity equals approximately 1 M.
Calculate the molarity of a 10 percent aqueous solution of HCl?
molarity = mol / litre The concentration is 10% HCl in water, assuming this is expressed in w/v (weight to volume) as this is the normal way. The density of 10% HCl is unknown but will be estimated to be the same as water (although slightly incorrect), since no data is given. 1 L of which 10% are HCl is assumed to weigh 1000 grams. 10% HCl x 1000g = 100g of HCl. 100g of HCl is present in 1 L. The mw of HCl = 36.5g/mol, 100g/(36.5g/mol) = 2.74mol is present in 1 L. The molarity is 2.74mol / 1 L = 2.7 M (two significant figures) (Looking up hydrochloric acid in wikipedia tells us that the density of a 10% solution is actually 1048g/L and the actual molarity becomes 2.87M. The calculated number was close enough, but it shows that the density is important. Molality on the other hand is mol/kg, so with molality we can skip the unknown density problem. For practical purposes, molarity is still the mostly used one, because volume is easier to measure than weight in the laboratory when handling toxic solvents that are unhealthy to inhale.)
What is the molarity of a silver nitrate that contains 42.5g AgNO3 in 100mL of solution?
First we need to convert grams(g) to moles(mol) and mL to L, since M(molarity)=mol/L.Ag=107.868N=14O=16 x3=48AgNO3 =169.868 g/mol42.5g x 1 mol/169.868g = .25mol AgNO3100mL x 10-3 L/ 1mL = .1LM=mol/L.25mol/.1L = 2.5M AgNO3
What is the molarity of a 5.00x 10 2ml solution containing 249g of k?
Molarity = moles of solute/Liters of solution some conversion needed 5.00 X 102 ml = 0.5 liters ------------------------------------- 249 grams K (1 mole K/39.10 grams = 6.37 moles potassium ------------------------------------------------------------------------------- Molarity = 6.37 mole K/0.5 Liters = 12.7 M K -----------------( as expected, highly concentrated solution )
What is the molartiy of 0.5 liters of a solution with five moles of sucorse in it?
Molarity = moles of solute/Liters of solution Molarity = 5 moles sucrose/0.5 Liters = 10 M ----------
What is the molarity of 10 moles of salt dissolved in 20 liters of water?
The molarity of the salt solution can be calculated by dividing the number of moles of solute (salt) by the volume of solution in liters. In this case, the molarity would be 10 moles / 20 liters = 0.5 moles per liter (M).
How do you find molarity of NaCl in a saturated solution?
Saturated is 36 - 40 g / 100 mL : Divide grams by the molar mass 58.5 g/mol NaCl and you'll find mol/100 mL Multiplying this value by 10 (= dL/L) and you find mol/L. Doing an estimation gives me approx. 7 mol/L, my calculator is tilted, so I hope your's doing better.
