Divide 175 by 750 and multiply by 1000 to get g/l. This gives you 233.3333g/litre. The molecular weight for KNO3 is 101.1g/mol. 233.333/101.1 is 2.31 molar.
You want to get the concentration that would be in a litre. for every 750ml, there is 1 mol. so 1/750, x1000 will give you 1.333 molar. i.e. 1.333 moles in every litre.
Well potassium nitrate has a molecular weight of 101. If there are 346g in 750ml there will be 346 x 1000/750 = 461.334 g in 1 liter. The solution is thus 461.334/101 = 4.57 molar (2 decimal places).
To find the molarity of the sugar solution, we first need to convert the mass of glucose to moles. The molar mass of glucose (C6H12O6) is 180 g/mol. So, 80 g of glucose is equal to 80/180 = 0.444 moles. Next, calculate the molarity by dividing moles of glucose by liters of solution (0.75 L), Molarity = 0.444 moles / 0.75 L = 0.592 M.
MW NaOH is 23+16+1 = 40. 4.5g in 750ml is 6.0g in 1L. Molarity is 6/40 = 0.15 OH- concentration is 0.15, pOH is -log100.15 = 0.82 H+ concentration is 10-14/0.15 = 6.67x10-13 pH is -log10 6.67x10-13 = 12.18
That depends on whether it s 750ml of lead, 750ml of foam, or something in between.
To find the mass of the solute (lithium sulfide) in 750mL of 0.188M solution, you need to multiply the volume of the solution (750mL) by the molarity (0.188 mol/L) and the molar mass of lithium sulfide (Li2S). First, calculate the number of moles in 750mL of 0.188M solution, then convert moles to grams using the molar mass of Li2S (45.88 g/mol).
First, convert the mass of NaNO3 to moles using the molar mass of NaNO3. Then, calculate the molarity by dividing the moles of NaNO3 by the volume of the solution in liters. Molarity (M) = moles of solute / volume of solution in liters.
You want to get the concentration that would be in a litre. for every 750ml, there is 1 mol. so 1/750, x1000 will give you 1.333 molar. i.e. 1.333 moles in every litre.
Well potassium nitrate has a molecular weight of 101. If there are 346g in 750ml there will be 346 x 1000/750 = 461.334 g in 1 liter. The solution is thus 461.334/101 = 4.57 molar (2 decimal places).
You have 2.5 moles in 750ml. However molar means per 1000ml. Therefore 2.5/750*1000 gives you your answer. The answer is 3.333 molar.
To find the molarity of the sugar solution, we first need to convert the mass of glucose to moles. The molar mass of glucose (C6H12O6) is 180 g/mol. So, 80 g of glucose is equal to 80/180 = 0.444 moles. Next, calculate the molarity by dividing moles of glucose by liters of solution (0.75 L), Molarity = 0.444 moles / 0.75 L = 0.592 M.
Molarity of a solution is the number of moles of the solute divided by the volume of the solution (in liters). If 750 ml of 20M HCl is mixed with 250 ml of 60M HCl, we first find the total number of moles of HCl in our new solution. Using that same formula, M=moles/V, we cansee that moles=MV. In the first solution we have (20M)(0.750L) = 15 moles. In the second, (60M)(0.250L) = 15 moles, so we have a total of 30 moles in our new solution, which also has a volume of 750mL + 250mL = 1L. The molarity of the new solution is 30 moles/1L = 30M
MW NaOH is 23+16+1 = 40. 4.5g in 750ml is 6.0g in 1L. Molarity is 6/40 = 0.15 OH- concentration is 0.15, pOH is -log100.15 = 0.82 H+ concentration is 10-14/0.15 = 6.67x10-13 pH is -log10 6.67x10-13 = 12.18
750ml
To find 5% of 750ml, you would multiply 750ml by 0.05 (which is the decimal equivalent of 5%). 750ml x 0.05 = 37.5ml. Therefore, 5% of 750ml is 37.5ml.
The concentration of HCl is 11,66 g/L.
750ml + 750ml = 1500ml, which is equal to 1.5 liters.