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Can you prepare 1 liter of a .5-molar glucose solution?
To prepare a 0.5 M glucose solution in 1 liter of water, you would need to dissolve 90.08 grams of glucose in enough water to make up the total volume of 1 liter. Start by weighing out 90.08 grams of glucose, add it to a container, and then add enough water to make the total volume up to 1 liter.
What is the molarity of a solution made by dissolving 23.4g of sodium sulphate in enough water to make up a 125ml solution?
To find the molarity, first calculate the number of moles of sodium sulphate using its molar mass. Sodium sulphate's molar mass is 142.04 g/mol. Next, divide the number of moles by the volume in liters (125 ml = 0.125 L) to get the molarity. This will give you the molarity of the sodium sulphate solution.
What is the molarity of a solution made by dissolving 3.09 moles of Nacl in 1.50 L of solution?
what is the molarity of a solution prepared by dissolving 36.0g of NaOH in enough water to make 1.50 liter of solution?
What is the molarity of a solution formed by mixing 20.0 g sulfuric acid with enough water to make 500.0 mL of solution?
To find the molarity, start by converting grams of sulfuric acid to moles. the molar mass of sulfuric acid (H2SO4) is 98.08 g/mol. Divide the moles by the volume in liters (500.0 mL = 0.5 L) to get the molarity. Molarity = moles/volume (L).
What is the molarity of a solution prepared by dissolving 1.56 grams of gaseous HCl in enough water to make 26.8 mL of solution?
Find moles of HCl first. 1.56 grams HCl (1mole HCl/36.458 grams) = 0.0428 moles HCl Molarity = moles of solute/volume of solution Molarity = 0.0428 moles/26.8 ml = 0.00160 milli-Molarity, or more to the point; = 1.60 X 10^-6 Molarity of HCl
How do you determine the molarity of a solution containing 18.2g C6H12O6and enough water to reach 6.3L?
Moles of solute ---------------- Liters of solution So, convert your grams to moles by dividing by the molar mass (add together the atomic masses of the solution) and then that will give you your moles. Divide that number by your 6.3 Liters. That number is your molarity.
What mass of solution would result if 81g of glucose(C6H12O6) is added to enough water to make a solution of 15.0 percent by mass?
To determine the mass of the solution, we need to calculate the total mass of the solution when 81g of glucose is added. Since the solution is 15.0% glucose by mass, the remaining 85.0% is water. Therefore, the total mass of the solution can be calculated using the mass of glucose added and the percentage of water. This would result in a total mass of solution greater than 81g due to the addition of water to dissolve the glucose.
The molecular mass of glucose C6H12O6 is 180 g To make a 0.5 M solution of glucose you should do what?
Dissolve 90 g of glucose in a small volume of water, and then add more water until the total volume of the solution is 1 L.
Can you prepare 1 liter of a .5-molar glucose solution?
To prepare a 0.5 M glucose solution in 1 liter of water, you would need to dissolve 90.08 grams of glucose in enough water to make up the total volume of 1 liter. Start by weighing out 90.08 grams of glucose, add it to a container, and then add enough water to make the total volume up to 1 liter.
What is the molarity of a solution made by dissolving 23.4g of sodium sulphate in enough water to make up a 125ml solution?
To find the molarity, first calculate the number of moles of sodium sulphate using its molar mass. Sodium sulphate's molar mass is 142.04 g/mol. Next, divide the number of moles by the volume in liters (125 ml = 0.125 L) to get the molarity. This will give you the molarity of the sodium sulphate solution.
How many moles are present in 21.5 g of NaCl?
A student placed 15.5 g of glucose (C6H12O6) in a volumetric flask, added enough water to dissolve the glucose by swirling, then carefully added additional water until the 100. mL mark on the neck of the flask was reached. The flask was then shaken until the solution was uniform. A 40.0mL sample of this glucose solution was diluted to 0.500 L. How many grams of glucose are in 100. mL of the final solution?
What is the molarity of a solution made by dissolving 3.09 moles of Nacl in 1.50 L of solution?
what is the molarity of a solution prepared by dissolving 36.0g of NaOH in enough water to make 1.50 liter of solution?
How can you prepare 50mm glucose?
To prepare a 50mm glucose solution, you would need to dissolve 9g of glucose in enough water to make 100mL of solution. This would give you a solution with a concentration of 50mm (millimolar).
To 225 mL of a 0.80M solution of KI a student adds enough water to make 1.0 L of a more dilute KI solution What is the molarity of the new solution?
0.18M
What is the molarity of a solution formed by mixing 20.0 g sulfuric acid with enough water to make 500.0 mL of solution?
To find the molarity, start by converting grams of sulfuric acid to moles. the molar mass of sulfuric acid (H2SO4) is 98.08 g/mol. Divide the moles by the volume in liters (500.0 mL = 0.5 L) to get the molarity. Molarity = moles/volume (L).
Calculate the molar it’s oh a solution that contains 15.7 of CaCO3 dissolved in enough water to make 275mL of solution?
0.570 M (note the capital M, this is molarity.)
What is the molarity of 20.2 g of potassium nitrate in enough water to make 250.0 mL of solution?
To find the molarity, first calculate the number of moles of potassium nitrate using its molar mass (101.1 g/mol). This comes out to 0.2 moles. Then, divide the moles by the volume of the solution in liters (0.250 L) to get the molarity, which is 0.8 M.
