I assume you mean ethanol + KOH? if so, in order to prevent co-precipitation of piperine and the resin acids, dilute ethanolic KOH is added to the concentrated extract to keep acidic materials in solution as their potassium salts (acid/base rxn occurs). basically it keeps impurities in solution, while piperine precipitates out.
"http://wiki.answers.com/Q/Why_do_you_use_KOH_ethanol_for_the_isolation_of_piperine_and_What_are_their_uses"
By addition of 10% ethanolic KOH, water and HCl
dissolve KOH powder in ethanol
K+ and OH- is KOH -----------
Molar mass KOH = 56g/mol and 0.002 N KOH = 0.002 moles/L0.002 moles/L x 56 g/mole = 0.112 g/LDissolve 0.113 grams KOH in 1 liter or methanol, or any fraction/multiple thereof. For example, dissolve 0.0113 g KOH in 100 mls or dissolve 0.226 g in 2 liters of methanol.
Molar mass of KOH = 39.1+16.0+1.0 = 56.1Amount of KOH = mass of sample / molar mass = 32/56.1 = 0.570mol
By addition of 10% ethanolic KOH, water and HCl
dissolve KOH powder in ethanol
In all the compounds where O is bonded to H the bond is covalent. For example H2O water, C2H5OH, ethanol KOH potssium hydroxide
K+ and OH- is KOH -----------
Molar mass KOH = 56g/mol and 0.002 N KOH = 0.002 moles/L0.002 moles/L x 56 g/mole = 0.112 g/LDissolve 0.113 grams KOH in 1 liter or methanol, or any fraction/multiple thereof. For example, dissolve 0.0113 g KOH in 100 mls or dissolve 0.226 g in 2 liters of methanol.
Molar mass of KOH = 39.1+16.0+1.0 = 56.1Amount of KOH = mass of sample / molar mass = 32/56.1 = 0.570mol
Koh Samui is in Thailand
KOH is potassium hydroxide.
KOH is Potassium Hydroxide.
KOH is potassium hydroxide.
KOH is a strong electrolyte
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