They are further away from the nucleus and easier to remove (requires less energy), i.e. first ionization is less.
First make the m.o (molecular orbital) diagram. If the electrons are paired in an orbital then it is diamagnetic . If the electrons are not paired then it is paramagnetic.
the 4s electrons are removed first.
The first orbital has only an s orbital, which has room for 2 electrons. The second orbital has s and p orbitals, which have room for 2 and 6 electrons respectively. The 3rd orbital has s, p, and d orbitals, which have room for 2, 6, and 10 electrons respectively. Hope that helps
Every orbital is different. 2 can occupy the first orbital then 8 can occupy mostly the rest. When you start getting really low on the periodic table orbitals start holding 16, but not till u get really low
There are two electrons in the first shell of neon. Its complete electronic configuration is 2,8
Any orbital is complete when it contains 2 electrons.
[Xe] 4f^14 5d^8
2 electrons.
The electrons fill in the lowest energy orbital that is available. Electrons in the 4s orbital have a lower energy level than electrons in the 3p orbital, so the 4s orbitals are filled with electrons first.
17 protons and 18 neutrons in the nucleus 2 electrons in the first orbital. 8 electrons in the second orbital. 7 electrons in the third orbital.
Be (beryllium) has four electrons total: the first orbital, the 1s orbital, has two, which leaves two electrons in the outer shell.
4 electrons. First orbital is the 1s which has 2 electrons. Second orbital is the 2s which has 2 electrons.
Yes
No, Q is the outermost orbital. K is the first one.
there are 2
If you are filling in the electrons it will be in the 4d orbital. If you are removing electrons the first to come out is in the 5s electrons since transition metals lose 's' electrons before 'd' electrons
First make the m.o (molecular orbital) diagram. If the electrons are paired in an orbital then it is diamagnetic . If the electrons are not paired then it is paramagnetic.