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Which of following molecules cannot be humans sucrose maltose cellulose fructose?
Cellulose cannot be ingested by humans because our bodies lack the necessary enzymes to break down its beta-linkages. Sucrose, maltose, and fructose are all types of sugars that can be metabolized by the human body for energy.
Can we find yellow adulteration by chana dal and iodine solution?
No, you cannot find yellow adulteration by chana dal using iodine solution. Iodine solution is typically used to detect the presence of starch in food products. Yellow coloring in chana dal may be due to artificial coloring agents or other adulterants that may require different testing methods for detection.
A simple sugar that cannot be hydrolysed to smaller units?
Monosaccharides are simple sugars that cannot be hydrolyzed into smaller units. They are the most basic unit of carbohydrates and include glucose, fructose, and galactose. These sugars are typically the building blocks for more complex carbohydrates like disaccharides and polysaccharides.
What color does saliva turn into with the Benedict's solution?
Benedict's solution changes colors (blue to green to yellow to orange to red) in the presence of "reducing" sugars, which are not normally present in saliva. An interesting experiment, however, is testing table sugar with Benedict's solution. Table sugar is a glucose sugar joined to a fructose sugar, so they cannot react with the Benedict's solution and no color change occurs. Put table sugar in your mouth for a few moments, and then test the saliva. Now the Benedict's solution will react! (The reason: saliva has an enzyme, amylase, which breaks the glucose and fructose apart so that they can react to the Benedict's.)
Can sucrose conduct electricity as a solid or in-solution?
Sucrose can not conduct significant electric currents in either solid form or in solution in water, because sucrose does not contain ions in its solid form and does not ionize when it dissolves in water.
Why is lugol's solution cannot detect simple sugar?
Lugol's solution is a reagent commonly used to detect the presence of starch. It cannot detect simple sugars because its active ingredient, iodine, does not react with simple sugars like glucose or fructose. Simple sugars do not contain the necessary chemical structure for the iodine in Lugol's solution to form a complex with, so they remain undetected in this test.
Why you cannot filtrate a solution?
A filtrate is already in solution.
What is an example of monosaccharaides?
Some examples: glucose, fructose, galactose, xylose, ribose.
Is High Fructose Corn Syrup a completely different chemical from regular fructose and if so what is the chemical formula?
High fructose corn syrup, HFCS, is a blend of two simple sugars, fructose and glucose. Both sugars have the same chemical formula, C6H12O6, but have unique chemical structures. "Regular" fructose, found in fruit or sucrose ( table sugar) has the same chemical formula. Sucrose, however, is a disaccharide of fructose and glucose which means that the fructose and glucose are chemically linked. Therefore, the ratio of the fructose to glucose in sucrose is precisely 50:50, 1:1, and the %fructose cannot exceed 50%. This is not the case with HFCS. Depending on the needs of the manufacturers the %fructose can range from 42% to 90%. Dairy and baked products use 42%, Pepsi and Coke use 55% fructose, and low-cal products may contain as much as 90% fructose.
Which of the following cannot be in the solution set of 1?
Nothing that follows can be in the solution set of 1 so all of it cannot.
Which of following molecules cannot be humans sucrose maltose cellulose fructose?
Cellulose cannot be ingested by humans because our bodies lack the necessary enzymes to break down its beta-linkages. Sucrose, maltose, and fructose are all types of sugars that can be metabolized by the human body for energy.
Can we find yellow adulteration by chana dal and iodine solution?
No, you cannot find yellow adulteration by chana dal using iodine solution. Iodine solution is typically used to detect the presence of starch in food products. Yellow coloring in chana dal may be due to artificial coloring agents or other adulterants that may require different testing methods for detection.
How do you change sucrose to glucose?
Sucrose is a disaccharide composed of glucose and fructose. A sucrase will hydrolyze sucrose into both constitute parts. You will be left with glucose and fructose, but you cannot directly transform sucrose to glucose.
Which of the following cannot be digested by humans-sucrose maltose cellulose or fructose?
Cellulose cannot be digested by humans.Cellulosecellulosehumans cannot digest cellulosecelluloseCelluloseCellulose (aka Fiber) can not be digested by humans because, we don't have the bacteria needed to break down cellulose. Sucrose, Maltose, and Fructose are all disaccharides (carbohydrates/sugars) and are all able to be broken down to glucose in the body.
A simple sugar that cannot be hydrolysed to smaller units?
Monosaccharides are simple sugars that cannot be hydrolyzed into smaller units. They are the most basic unit of carbohydrates and include glucose, fructose, and galactose. These sugars are typically the building blocks for more complex carbohydrates like disaccharides and polysaccharides.
What color does saliva turn into with the Benedict's solution?
Benedict's solution changes colors (blue to green to yellow to orange to red) in the presence of "reducing" sugars, which are not normally present in saliva. An interesting experiment, however, is testing table sugar with Benedict's solution. Table sugar is a glucose sugar joined to a fructose sugar, so they cannot react with the Benedict's solution and no color change occurs. Put table sugar in your mouth for a few moments, and then test the saliva. Now the Benedict's solution will react! (The reason: saliva has an enzyme, amylase, which breaks the glucose and fructose apart so that they can react to the Benedict's.)
What is known about the lines of the equations in a system of equation when the solution set is all real numbers?
No answer is possible. As soon as you have one valid line, all points that are not on that line cannot be part of the solution set. Therefore the solution set cannot be all real numbers.No answer is possible. As soon as you have one valid line, all points that are not on that line cannot be part of the solution set. Therefore the solution set cannot be all real numbers.No answer is possible. As soon as you have one valid line, all points that are not on that line cannot be part of the solution set. Therefore the solution set cannot be all real numbers.No answer is possible. As soon as you have one valid line, all points that are not on that line cannot be part of the solution set. Therefore the solution set cannot be all real numbers.
