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Why was it necessary to have an excess of ca2 ions to precipitate the unknown carbonates?
Having an excess of Ca2+ ions helps ensure that all the CO32- ions in the solution react with Ca2+ to form the calcium carbonate precipitate. If there is a higher concentration of Ca2+ ions compared to the CO32- ions, it increases the likelihood of complete precipitation and minimizes the risk of having leftover CO32- ions in solution. This excess of Ca2+ ions helps drive the precipitation reaction to completion.
What else can I help you with?
How do you test for sulphate ions?
add barium chloride or barium nitrate to a solution containing sulphate ions SO4 2-. To the same solution add hydrochloric acid in excess. OBSERVATIONS, a white precipitate which is insoluble in excess acid confirms presence of SO42- IF IT DISSOLVES then it confirms SO32- ----------------------------------------- 1) Add barium nitrate solution under acidic conditions (use an equal volume of hydrochloric acid) to the unknown solution 2) A white precipitate of barium sulphate forms if sulphate ions are present
What mass of the precipitate could be produced by adding 100.0ml of 0.887 m agno3 to a na3po4 solution assume that the sodium phosphate reactant is present in excess?
To find the mass of the precipitate that forms when 100.0mL of 0.887M AgNO3 is added to a Na3PO4 solution, you need to determine the limiting reactant. Since Na3PO4 is in excess, AgNO3 is the limiting reactant. Calculate the moles of AgNO3 using its molarity and volume, then use the mole ratio between AgNO3 and the precipitate to find the moles of the precipitate. Finally, convert the moles of the precipitate to mass using its molar mass.
Why do the solution of the white precipitate of Zinc hydroxide dissolve in excess of Ammonium hydroxide?
The white precipitate of zinc hydroxide dissolves in excess ammonium hydroxide because of the formation of the complex ion [Zn(NH3)4]2+. This complex ion is soluble in water, leading to the dissolution of the precipitate. The excess ammonium hydroxide provides additional ammonia molecules to form more of the soluble complex ions, increasing the solubility of zinc hydroxide.
Precipitate of salicylic acid dissolves after addition of excess sulphuric acid?
The precipitate of salicylic acid dissolves in excess sulphuric acid due to the formation of a complex between salicylic acid and sulphuric acid, which increases the solubility of the precipitate. This reaction results in the formation of a colorless solution, as the salicylic acid is converted into its conjugate base form.
How many mol of AgCl can be precipitated by adding a solution containing 0.100 mol of AgNO3 to a solution containg excess NaCl?
One mole of AgNO3 reacts with one mole of NaCl to form one mole of AgCl precipitate. Therefore, 0.100 mol of AgNO3 will form 0.100 mol of AgCl precipitate when reacted with excess NaCl.
Name a salt which gives white precipitate on ammonium hydroxide solution and is insoluble in excess?
One such salt would be aluminum chloride since it is soluble but when reacted with ammonium hydroxide, the insoluble aluminum hydroxide forms a precipitate. Not sure what is meant by "is insoluble in excess", however.
How do you test for sulphate ions?
add barium chloride or barium nitrate to a solution containing sulphate ions SO4 2-. To the same solution add hydrochloric acid in excess. OBSERVATIONS, a white precipitate which is insoluble in excess acid confirms presence of SO42- IF IT DISSOLVES then it confirms SO32- ----------------------------------------- 1) Add barium nitrate solution under acidic conditions (use an equal volume of hydrochloric acid) to the unknown solution 2) A white precipitate of barium sulphate forms if sulphate ions are present
What mass of the precipitate could be produced by adding 100.0ml of 0.887 m agno3 to a na3po4 solution assume that the sodium phosphate reactant is present in excess?
To find the mass of the precipitate that forms when 100.0mL of 0.887M AgNO3 is added to a Na3PO4 solution, you need to determine the limiting reactant. Since Na3PO4 is in excess, AgNO3 is the limiting reactant. Calculate the moles of AgNO3 using its molarity and volume, then use the mole ratio between AgNO3 and the precipitate to find the moles of the precipitate. Finally, convert the moles of the precipitate to mass using its molar mass.
Why do the solution of the white precipitate of Zinc hydroxide dissolve in excess of Ammonium hydroxide?
The white precipitate of zinc hydroxide dissolves in excess ammonium hydroxide because of the formation of the complex ion [Zn(NH3)4]2+. This complex ion is soluble in water, leading to the dissolution of the precipitate. The excess ammonium hydroxide provides additional ammonia molecules to form more of the soluble complex ions, increasing the solubility of zinc hydroxide.
Precipitate of salicylic acid dissolves after addition of excess sulphuric acid?
The precipitate of salicylic acid dissolves in excess sulphuric acid due to the formation of a complex between salicylic acid and sulphuric acid, which increases the solubility of the precipitate. This reaction results in the formation of a colorless solution, as the salicylic acid is converted into its conjugate base form.
What is observe when aqueous ammonia is added in excess to a silver chloride solution?
When aqueous ammonia is added in excess to a solution of silver chloride, the white precipitate of silver chloride dissolves to form a colorless, tetrahedral complex ion called [Ag(NH3)2]+. This complex ion is soluble in excess ammonia due to the formation of a stable coordination complex.
What colour is the precipitate from sulfate ions?
This depends on what the metal cation is. If the metal cation is a transition metal ion then it would be coloured, like in the case of FeSO4 which is blue/green. Many sulfates are soluble and if there is excess solvent no precipitate would be observed.
What is the zone of equivalence in precipitation test?
The zone of equivalence in a precipitation test refers to the point at which optimal amounts of antigen and antibody have reacted together to form a visible precipitate. This zone indicates the point where antibody and antigen are present in the right proportions for a reaction to occur. Outside this zone, either excess antigen or excess antibody may hinder the formation of a visible precipitate.
How many mol of AgCl can be precipitated by adding a solution containing 0.100 mol of AgNO3 to a solution containg excess NaCl?
One mole of AgNO3 reacts with one mole of NaCl to form one mole of AgCl precipitate. Therefore, 0.100 mol of AgNO3 will form 0.100 mol of AgCl precipitate when reacted with excess NaCl.
Why is a twofold excess of chloride added to precipitate the silver?
Excess chloride ions are added to ensure that all the silver ions present in the solution react to form the silver chloride precipitate. This prevents unwanted silver ions from remaining in the solution, preventing incomplete precipitation. Twofold excess is typically used to ensure that there are enough chloride ions to react with all the silver ions present.
A solution suddenly forms a precipitate when agitated It is supersaturated saturated unsaturated or concentrated?
The solution is supersaturated. This means it contains more solute than it would normally hold at the given temperature. Agitation causes the excess solute to come out of solution and form a precipitate.
Why are there blue precipitate at the end of redox titration?
The blue precipitate may indicate the presence of excess indicator in the solution. In redox titrations, the indicator changes color when the reaction reaches its endpoint. If too much indicator is added, it can form a colored precipitate due to its reaction with the titrant, which can obscure the endpoint of the titration. It is important to carefully control the amount of indicator to avoid this issue.
