Barium chloride: gravimetric determination of sulfate
Sodium carbonate: qualitative determination of some metals
Na2O + H2O
FeSO4+BaCl2=>FeCl2+BaSO4
For ppt ion so4
solution containig (3.3)gm na2co3 .h2o in (15ml)
In solution - neutral
Na2O + H2O
BaCl2 is barium chloride, Na2CO3 is sodium carbonate, NaCl is sodium chloride BaCO3 is barium carbonate; the reaction is:BaCl2 + Na2CO3 = BaCO3 + 2NaClBarium carbonate is a water insoluble white precipitate.
FeSO4+BaCl2=>FeCl2+BaSO4
For ppt ion so4
solution containig (3.3)gm na2co3 .h2o in (15ml)
In solution - neutral
yes it is
The chemical formula of sodium carbonate is Na2CO3. A solution hasn't a formula.
A 0.5N Na2CO3 used in determining the concentration of an unknown HCl solution has a weight of 1.06 grams. To find the weight, you need to first find out how many moles there are by calculating molarity times volume.
.256 molar= 256 mols of solute per 1000ml of solution. Since there are 1000ml in 1L, there are 256 mols of BaCl2 for every liter. Multiply this by 1.5 and you get a total of 384 mols of BaCl2 in 1.5L of a .256 molar solution
Test for the anions,according to your word,i think you got the salts,so, use these reagents HCL,BACL2,Adding bacl2 and Hcl to Naso4-white ppt observed in soluble,but barium chloride will give no ppt...so probem solved
S2- + BaCl2 ------> BaS + 2Cl-