BaCl2 is barium chloride, Na2CO3 is sodium carbonate, NaCl is sodium chloride BaCO3 is barium carbonate; the reaction is:
BaCl2 + Na2CO3 = BaCO3 + 2NaCl
Barium carbonate is a water insoluble white precipitate.
When BaCl2 and NaCl are mixed together, no reaction will occur because Ba and Na have similar reactivities. Both BaCl2 and NaCl are ionic compounds that will remain as separate ions in solution.
The solution of 0.1M NaCl will have the highest electrical conductivity among the three options provided. This is because NaCl dissociates completely in water to produce more free ions, which increases the conductivity. BaCl2 and AlCl3 do not dissociate as completely as NaCl, resulting in fewer free ions and lower conductivity.
This equation does not balance because 2 chlorine salts do not react with eachother. However, they are both highly soluable in water. By adding H2O, this equation can be balanced.
This equation is BaCl2 (aq) + Na2SO4 (aq) -> 2 NaCl (aq) + BaSO4 (s).
The molecular weight of NaCl is 58.44g/mol, the atomic mass of Na is 22.99 and the atomic mass of Cl is 35.45 when added together we get 58.44 g/mol.The molecular weight of BaCl2 is 208.233g/mol, the atomic mass of Ba is 137.327 and the atomic mass of Cl2 is (35.453)(2) = 70.906 when added together we get 208.233g/mol
The chemical formula of sodium sulfate is Na2SO4. The chemical formula of barium chloride is BaCl2. BaCl2 + Na2SO4-----------BaSO4 + 2 NaCl BaSO4 is a white, practically insoluble in water precipitate; this property is important in gravimetric analysis.
Ooh. Somebody doesn't like doing their chem homework. Luckily I just happened to do that exact same equation. 1 BaCl2 +1 Na2S --> 2 NaCl(Salt! :D) +1 BaS
NaCl doesn't react with KNO3.NaCl + AgNO3 = NaNO3 + AgCl(s)NaOH + HCl = NaCl + H2ONa2CO3 + 2 HCl = 2NaCl + CO2 + H2OBaCl2 + H2SO4 = BaSO4(s) + 2 HClCuSO4 and Zn(NO3)2 doesn't react.
BaCl2(aq) + Na2SO4 (aq) ------> BaSO4(s) + 2NaCl(aq)
The balanced equation for barium chloride (BaCl2) and sodium carbonate (Na2CO3) mixing to form barium carbonate (BaCO3) and sodium chloride (NaCl) is: BaCl2 + Na2CO3 -> BaCO3 + 2NaCl.
Test for the anions,according to your word,i think you got the salts,so, use these reagents HCL,BACL2,Adding bacl2 and Hcl to Naso4-white ppt observed in soluble,but barium chloride will give no ppt...so probem solved
BaCl2 is added to the NaCl solution to precipitate any sulfate ions present as BaSO4, which is insoluble. CaCO3 is then added to remove any excess Ba2+ ions by forming BaCO3, which is also insoluble. This purification process helps to remove impurities like sulfate ions and any excess barium ions from the sodium chloride solution.