yes, it does react. It produces NaCl + CO2 + H2O
so it looks like this...
NaHCO3 + HCl ---> NaCl + CO2 + H2O
CO2 as gas H2O as a liquid NaCl as aqueous
The answer to the conversion is that 35.0 grams of hydrochloride (HCL) equals 0.76 moles. The conversion rate is 35.0 grams divided by 46 gram per mole. A mole is the molecular weight of a substance.
The answer is 5 m L sodium bicarbonate, 1 M solution.
12.5 mL * 5.0 (m)mol/(m)L HCl = 62.5 mmol spilled HClneeds62.5 mmol NaHCO3 = 62.5 mmol * 84.01 (m)g/(m)mol NaHCO3 = 5250 mg NaHCO3 = 5.25 g pure NaHCO3
Sodium hydroxide in a pure form is a solid, so you cannot dissolve anything in it. Normally, NaOH is used as an aqueous solution. But salicylic acid dissolves in water, so the presence of NaOH in the water is irrelevant to the solubility of salicylic acid. It is the water, not the NaOH, that dissolves the salicylic acid.
CO2 as gas H2O as a liquid NaCl as aqueous
The answer to the conversion is that 35.0 grams of hydrochloride (HCL) equals 0.76 moles. The conversion rate is 35.0 grams divided by 46 gram per mole. A mole is the molecular weight of a substance.
Baking soda is sodium bicarbonate, NaHCO3. Sodium bicarbonate and hydrochloric acid, HCl, react to form sodium chloride, NaCl and carbonic acid, H2CO3. NaHCO3 + HCl ---> NaCl + H2CO3
The answer is 5 m L sodium bicarbonate, 1 M solution.
Several part problem. Get molarity of NaHCO3. (150 ml)( M NaHCO3) = (150 ml)(0.44 M HCl) = 0.44 M NaHCO3 --------------------------- get moles NaHCO3 ( 150 ml = 0.150 Liters ) 0.44 M NaHCO3 = moles NaHCO3/0.150 Liters = 0.066 moles NaHCO3 ---------------------------------------get grams 0.066 moles NaHCO3 (84.008 grams/1 mole NaHCO3) = 5.54 grams NaHCO3 needed ---------------------------------------------answer
12.5 mL * 5.0 (m)mol/(m)L HCl = 62.5 mmol spilled HClneeds62.5 mmol NaHCO3 = 62.5 mmol * 84.01 (m)g/(m)mol NaHCO3 = 5250 mg NaHCO3 = 5.25 g pure NaHCO3
Sodium hydroxide in a pure form is a solid, so you cannot dissolve anything in it. Normally, NaOH is used as an aqueous solution. But salicylic acid dissolves in water, so the presence of NaOH in the water is irrelevant to the solubility of salicylic acid. It is the water, not the NaOH, that dissolves the salicylic acid.
The reactants are sodium bicarbonate (NaHCO3) and hydrochloric acid (HCl). These react to form sodium chloride (NaCl), water (H2O), and carbon dioxide (CO2) as products.
The balanced chemical equation for the reaction between sodium bicarbonate (NaHCO3) and hydrochloric acid (HCl) is: NaHCO3 + HCl → NaCl + H2O + CO2
Any chemical reaction is possible.
Salicylic acid is soluble in NaOH and insoluble in NaHCO3 and HCl. In NaOH, salicylic acid can form a salt through neutralization. In NaHCO3 and HCl, salicylic acid remains as a solid due to its low solubility in these solutions.
NaCl and HCl doesn't react.