Copper is a transition metal- these often give rise to colored salts. Sodium is an s block metal these are generally colorless. The reason is that transition metals ions have electrons in an outer d orbitals that can be excited to higher energy levels by visible light.
When copper sulfate is added to sodium hydroxide, a blue precipitate of copper hydroxide is formed. The color change observed is from the initial blue color of copper sulfate to the blue precipitate of copper hydroxide.
If you add copper sulfate to sodium hydroxide, a double displacement reaction will occur. The copper sulfate will react with the sodium hydroxide to form copper hydroxide, which is a blue solid, and sodium sulfate, which is a soluble compound. This reaction is often used in qualitative analysis to test for the presence of copper ions.
copper sulphate solution-blue sodium chloride (salt) solution-clear sodium nitrate solution- white to clear sodium sulphate solution- white copper sulphate solution-blue sodium chloride (salt) solution-clear sodium nitrate solution- white to clear sodium sulphate solution- white
In the balanced equation CuSO4 + 2NaOH → Cu(OH)2 + Na2SO4, copper sulfate (CuSO4) is a reactant. It reacts with sodium hydroxide (NaOH) to form copper hydroxide (Cu(OH)2) and sodium sulphate (Na2SO4).
The reaction between sodium hydroxide and copper sulfate will result in the formation of sodium sulfate and copper hydroxide. The products of this reaction will be a blue precipitate of copper hydroxide and a solution of sodium sulfate.
When copper sulfate is added to sodium hydroxide, a blue precipitate of copper hydroxide is formed. The color change observed is from the initial blue color of copper sulfate to the blue precipitate of copper hydroxide.
If you add copper sulfate to sodium hydroxide, a double displacement reaction will occur. The copper sulfate will react with the sodium hydroxide to form copper hydroxide, which is a blue solid, and sodium sulfate, which is a soluble compound. This reaction is often used in qualitative analysis to test for the presence of copper ions.
copper sulphate solution-blue sodium chloride (salt) solution-clear sodium nitrate solution- white to clear sodium sulphate solution- white copper sulphate solution-blue sodium chloride (salt) solution-clear sodium nitrate solution- white to clear sodium sulphate solution- white
In the balanced equation CuSO4 + 2NaOH → Cu(OH)2 + Na2SO4, copper sulfate (CuSO4) is a reactant. It reacts with sodium hydroxide (NaOH) to form copper hydroxide (Cu(OH)2) and sodium sulphate (Na2SO4).
I DONT KNOW
Nowhere. I assume you are talking about mixing solutions. The sodium ions and sulpahate ions remain in solution.
When copper sulfate and sodium hydroxide are mixed, a blue precipitate of copper hydroxide is formed. This is because the hydroxide ions from sodium hydroxide react with the copper ions from copper sulfate to form the insoluble copper hydroxide. The net ionic equation for this reaction is Cu^2+ (aq) + 2OH^- (aq) → Cu(OH)2 (s).
The reaction between sodium hydroxide and copper sulfate will result in the formation of sodium sulfate and copper hydroxide. The products of this reaction will be a blue precipitate of copper hydroxide and a solution of sodium sulfate.
When sodium chloride reacts with copper sulfate, sodium sulfate and copper chloride are formed. This is a double displacement reaction where the cations and anions of the two compounds switch partners.
Any reaction occur.
Biuret reagent is made up of sodium hydroxide and copper sulphate.
it contains sodium carbonate (inorganic), copper sulphate (inorganic) and sodium citrate (organic).