Here's that equation:
H2SO4 + 2LiOH => Li2SO4 + H2O
And gee, it's even a load of bollocks ;D
H2SO4 + 2LiOH => Li2SO4 + 2H2O
There, if you didn't put the 2 in front of water than you would get 4 hydrogen on one side and 2 oxygen while the other side would only have 2 hydrogen and one oxygen.
I believe the technical term for that correction is Pwned.
The reaction SO2 + H2O -> H2SO3 is a reaction where sulfur dioxide reacts with water to form sulfurous acid. To balance the equation, you would need to ensure that there are equal numbers of each type of atom on both sides of the equation.
The balanced chemical equation for the reaction between nitric acid (HNO3) and lithium hydroxide (LiOH) is: 2 HNO3 + 2 LiOH → 2 LiNO3 + 2 H2O
Mn(CH3COO)2 + 2NaOH ----> Mn(OH)2 + 2CH3COONa
2 NaOH + SO2 = H2O + Na2SO3
2 KOH + H2CO3 = 2 H2O + K2CO3
The reaction SO2 + H2O -> H2SO3 is a reaction where sulfur dioxide reacts with water to form sulfurous acid. To balance the equation, you would need to ensure that there are equal numbers of each type of atom on both sides of the equation.
The balanced chemical equation for the reaction between nitric acid (HNO3) and lithium hydroxide (LiOH) is: 2 HNO3 + 2 LiOH → 2 LiNO3 + 2 H2O
Mn(CH3COO)2 + 2NaOH ----> Mn(OH)2 + 2CH3COONa
2 NaOH + SO2 = H2O + Na2SO3
2 KOH + H2CO3 = 2 H2O + K2CO3
The balanced chemical equation for the neutralization reaction between sulfuric acid (H2SO4) and potassium hydroxide (KOH) to produce potassium sulfate and water is: H2SO4 + 2KOH → K2SO4 + 2H2O
Na3PO4+H2O->NaOH+H3PO4 just balance it.
When solid sodium hydroxide dissolves in water, the water heats up, demonstrating that the process of dissolving is exothermic for NaOH. (Very exothermic, in fact, releasing about 45kJ of heat per mole dissolved -- enough to heat a liter of H2O by 10C!) Since heat can be thought of as a product in an exothermic reaction, the equation is: NaOH (s) ---> Na+ (aq) + OH_ (aq) + 45kJ
2caoh + 2h2so4_2caso4 + 3h2o the equation is balance
The balanced equation for the reaction between lead(II) nitrate (Pb(NO3)2) and ammonium hydroxide (NH4OH) is: Pb(NO3)2 + 2NH4OH → Pb(OH)2 + 2NH4NO3 This reaction forms lead(II) hydroxide (Pb(OH)2) and ammonium nitrate (NH4NO3) as products.
Ca(OH)2 + 2HCl ---------> CaCl2 + 2H2OIonic Ca2+ + 2OH- + 2H+ +2Cl- -----------> Ca2+ +2Cl- + H2ONet Ionic: H+ + OH- -----------> H2O
if it is a redox reaction sometimes you can add water to help balance the equation