2s22p4
Gallium, or Ga has an electron configuration that begins with the base state of [Ar]. The outer shell is then 4s2 3d10 4p1
Valence electron configuration of zinc, abbreviated. [Ar] 4s2 3d10 Zinc's oxidation state is 2, so that 4s2 represents the valance electrons though they are at a lower energy level and the 3d10 gives you the full outer electron configuration.
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im guessing you mean valence shell electron configuration that would be: 5s^2 4d^10 5p^6
ns2np32nd answer :outer electron configuration is the same as valence electron , you can easily find it in the period table : using the number of the group :Group 1 : one, Group 2 :two , Group 3-12 cannot be found instead d electron count is used , group 13 : three , Group 14 : four ans so on until Group 18 : EightSo oxygen is in group 16 so it has 6 outer electron configuration or look to the Nobel gas notation : [He] 2s2 2p4 so count the power of last orbitals 2s 2p so : 6Read more: What_is_the_outer_electron_configuration_for_aluminum
The electron configuration of rutherfordium is: [Rn] 5f14 6d2 7s2.
halogens
The electron configuration of copper is 1s22s22p63s23p63d104s1.
1 electron in the s orbital
Gallium, or Ga has an electron configuration that begins with the base state of [Ar]. The outer shell is then 4s2 3d10 4p1
Valence electron configuration of zinc, abbreviated. [Ar] 4s2 3d10 Zinc's oxidation state is 2, so that 4s2 represents the valance electrons though they are at a lower energy level and the 3d10 gives you the full outer electron configuration.
Sodium is an element which has one electron in its outer electron shell, and which can obtain a more stable electron configuration by getting rid of that electron. This causes it to undergo chemical reactions with other elements such as oxygen or chlorine, which need to acquire electrons in order to obtain a more stable electron configuration. If sodium reacts with water, it is reacting with the oxygen in the water molecule. In the case of sodium chloride, the sodium has already reacted with chlorine to form that compound, and has given up its outer electron, so it no longer needs to react with oxygen in water.
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6. Oxygen has an electronic configuration of [He]2s22p4
im guessing you mean valence shell electron configuration that would be: 5s^2 4d^10 5p^6
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ns2np32nd answer :outer electron configuration is the same as valence electron , you can easily find it in the period table : using the number of the group :Group 1 : one, Group 2 :two , Group 3-12 cannot be found instead d electron count is used , group 13 : three , Group 14 : four ans so on until Group 18 : EightSo oxygen is in group 16 so it has 6 outer electron configuration or look to the Nobel gas notation : [He] 2s2 2p4 so count the power of last orbitals 2s 2p so : 6Read more: What_is_the_outer_electron_configuration_for_aluminum