10 characters minimum
15 or more is recommended
According to AR 25-2, Section IV, paragraph 4-12 b:
The IAM or designee will manage the password generation, issuance, and control process. If used, generate passwords in accordance with the BBP for Army Password Standards.
BBP for Army password standards are contained in 04-IA-O-0001, paragraph 5A:
(1) All system or system-level passwords and privileged-level accounts (e.g., root, enable, admin, administration accounts, etc.) will be a minimum of 15-character case-sensitive password changed every 60 days (IAW JTF-GNO CTO).
(2) All user-level, user-generated passwords (e.g., email, web, desktop computer, etc.) will change to a 14-character (or greater) case-sensitive password changed every 60 days.
From these two documents it would appear that the 10 character minimum is an outdated recommendation.
From this it would appear that the frequently repeated "8 character minimum" is outdated. Note that the only conditions where an 8 character password is allowed is:
(8) The use of eight character passwords are authorized when:
(I) The password generated is a purely random-generated authenticator from the complete alpha/numeric and special character sets and no user-configured passwords can replace, be generated, or accepted in lieu of the generated password. (For example: Credentialing system issues randomly generated authenticator AND enforce use of that authenticator to network resources.)
Or:
(II) Access to private applications is conducted over an approved 128-bit encrypted session between systems, and the application does not enforce local user access credentialing to a local network resources. (For example: User accesses local LAN connected system through traditional access procedures then accesses a web portal application over an SSL connection; the web portal password may be 8 characters.)
--- from 04-IA-O-0001, paragraph 5A
To find the length of the room, you can use the formula for the area of a rectangle, which is length multiplied by width. Given that the area is 252 square feet and the width is 18 feet, you can divide the area by the width to find the length. Therefore, the length of the room is 252 square feet divided by 18 feet, which equals 14 feet.
Using Pythagoras' theorem: 252-152 = 400 and the square root of this is 20 units in length.
The Tiber is 252 miles or 405km in length.
252 metres( 826.8 ft) in length and 26 metre width
252 square ft. Since the room is rectangular, you find the area by multiplying the length and the width, in this case being 18 and 14. 18x14=252 so the area, which is always in square units, is 252 square feet.
Doesn't seem likely, does it? A diagonal 50 times the length of the sides? Diagonal = sqrt(252 + 252), ie sqrt 1250(!) which is 35.36 to the nearest hundredth.
12 ft
Multiply width by length to get the area. The answer would be 252 square feet.
There are 36 inches to a yard. 36 × 11 = 396 inches Therefore 11 yards is longer than 252 inches.
It is 42 inches.
You don't without more information. Without knowing the length and width of the room or area linear feet has no meaning. Square footage is a measure of area and linear feet is only length or distance. If it is one foot wide then it would be 252 feet long. Or a million other lengths depending on the width and length of the area.
If the length of the enclosure is 21 feet then the width is 12 feet. 21*12 = 252 sq ft