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let us consider three inputs a,b,c and their sum as s, difference as d and carry as c and borrow b

in full adder circuit :-

s= a (XOR) b (XOR) c

carry = ab+ac+bc

in full subtractor :-

d= a (XOR) b (XOR) c

borrow b = a'b+a'c+bc

so on observing these two we notice that sum and difference are one and the same coming to carry and borrow the only difference is to obtain borrow from carry just complement the input a

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