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To take apart a M49, first ensure the weapon is unloaded and safe. Begin by removing the magazine and checking the chamber. Next, disassemble the upper and lower receiver by locating and removing the takedown pins. Finally, separate the bolt carrier group and other components as needed for cleaning or maintenance, following the manufacturer's guidelines for specific disassembly steps. Always refer to the user manual for detailed instructions and safety precautions.
What else can I help you with?
Are you able to take apart a Playmobil man?
no
How do you take a plug apart?
Not possible without breaking it.
If you drop a rock from a great height about how fast will it be falling after 5 seconds neglecting air resistance?
The object will be falling at 49 m/s.This is solved by multiplying the force of gravity (9.8 m/s) by the time you're calculating (5s).
How do you take apart the dash to put a aftermarket in?
youtube com/watch?v=dQw4w9WgXcQ
What are the instruction of ias computer?
InstructionTypeOpcodeSymbolicRepresentationDescriptionData transfer00001010000010010010000100000001000000100000001100000100LOAD MQLOAD MQ,M(X)STOR M(X)LOAD M(X)LOAD -M(X)LOAD |M(X)|LOAD -|M(X)|Transfer contents of register MQ to the accumulator ACTransfer contents of memory location X to MQTransfer contents of accumulator to memory location XTransfer M(X) to the accumulatorTransfer -M(X) to the accumulatorTransfer absolute value of M(X) to the accumulatorTransfer -|M(X)| to the accumulatorUnconditionalbranch0000110100001110JUMP M(X,0:19)JUMP M(X,20:39)Take next instruction from left half of M(X)Take next instruction from right half of M(X)Conditionalbranch0000111100010000JUMP+M(X,0:19)JUMP+M(X,20:39)If number in the accumulator is nonnegative, take next instruction from left half of M(X)If number in the accumulator is nonnegative , take next instruction from right half of M(X)Arithmetic0000010100000111000001100000100000001011000011000001010000010101ADD M(X)ADD |M(X)|SUB M(X)SUB |M(X)|MUL M(X)DIV M(X)LSHRSHAdd M(X) to AC; put the result in ACAdd |M(X)| to AC; put the result in ACSubtract M(X) from AC; put the result in ACSubtract |M(X)} from AC; put the remainder in ACMultiply M(X) by M(Q); put most significant bits of result in AC, put less significant bits in M(Q)Divide AC by M(X); put the quotient in MQ and the remainder in ACMultiply accumulator by 2 (i.e., shift left one bit position)Divide accumulator by 2 (i.e., shift right one bit position)Address modify0001001000010011STOR M(X,8:19)STOR M(X,28:39)Replace left address field at M(X) by 12 right-most bits of ACReplace right address field at M(X) by 12 right-most bits of AC
What is the answer to m squared -49?
That is an expression and this way it can only be factored. m^2 - 49 (m - 7)(m + 7) Wanting an answer implies an equation. m^2 - 49 = 0 m^2 = 49 m = +/- 7 same answer
What is the soultion to m x 49 equals 7?
m * 49 = 7 Divide both sides by 49 to get m = 7 / 49 So and the fraction 7 / 49 can simplify to 1 / 7 So m = 1/7
How do you tare down my ithaca m-49 22cal short long rifle?
Don't. This gun has parts held by pins. If you take it apart, you will end up at the gunsmith to put it back together- these are NOT meant to be taken down by the owner. Really.
If the time was 11.2 seconds to run the 100 M Dash in 49 strides how long did it take the runner to take one stride?
4.4
How many years apart is 31 and 49?
18
How do i factorise 49(m 2n)2 81(2m n)2?
Distribute the 49 and 81 first
How many meters in 49 feet?
There are approximately 14.9352 meters in 49 feet.
How many m are in 49 km?
49,000
How do you take the barrel out of a whirlpool dryer?
first you take the belt from around it take apart a few clamps and pull it striaght out.By the way ai,m only 12.
How do you take apart a smith and Wesson m and p 40cal?
Ask a gunsmith for help if you don't have the factory supplied manual.
Is .49 m bigger than .0031 km?
No.
Falling objects drop with an average acceleration of 9.8ms squared If an object falls from a tall building how long will it take before it reaches a speed of 49 ms?
Using the formula v = u + at, where v is final velocity, u is initial velocity, a is acceleration, and t is time, we can rearrange the formula to solve for time: t = (v - u) / a. Given that the initial velocity (u) is 0 m/s, the acceleration (a) is 9.8 m/s^2, and the final velocity (v) is 49 m/s, we can plug in these values to find the time it takes for the object to reach 49 m/s. t = (49 m/s - 0 m/s) / 9.8 m/s^2 = 5 seconds.
