What are the instruction of ias computer?

Answer 1

Instruction

Type

Opcode

Symbolic

Representation

Description

Data transfer

00001010

00001001

00100001

00000001

00000010

00000011

00000100

LOAD MQ

LOAD MQ,M(X)

STOR M(X)

LOAD M(X)

LOAD -M(X)

LOAD |M(X)|

LOAD -|M(X)|

Transfer contents of register MQ to the accumulator AC

Transfer contents of memory location X to MQ

Transfer contents of accumulator to memory location X

Transfer M(X) to the accumulator

Transfer -M(X) to the accumulator

Transfer absolute value of M(X) to the accumulator

Transfer -|M(X)| to the accumulator

Unconditional

branch

00001101

00001110

JUMP M(X,0:19)

JUMP M(X,20:39)

Take next instruction from left half of M(X)

Take next instruction from right half of M(X)

Conditional

branch

00001111

00010000

JUMP+M(X,0:19)

JUMP+M(X,20:39)

If number in the accumulator is nonnegative, take next instruction from left half of M(X)

If number in the accumulator is nonnegative , take next instruction from right half of M(X)

Arithmetic

00000101

00000111

00000110

00001000

00001011

00001100

00010100

00010101

ADD M(X)

ADD |M(X)|

SUB M(X)

SUB |M(X)|

MUL M(X)

DIV M(X)

LSH

RSH

Add M(X) to AC; put the result in AC

Add |M(X)| to AC; put the result in AC

Subtract M(X) from AC; put the result in AC

Subtract |M(X)} from AC; put the remainder in AC

Multiply M(X) by M(Q); put most significant bits of result in AC, put less significant bits in M(Q)

Divide AC by M(X); put the quotient in MQ and the remainder in AC

Multiply accumulator by 2 (i.e., shift left one bit position)

Divide accumulator by 2 (i.e., shift right one bit position)

Address modify

00010010

00010011

STOR M(X,8:19)

STOR M(X,28:39)

Replace left address field at M(X) by 12 right-most bits of AC

Replace right address field at M(X) by 12 right-most bits of AC