I think it is safe to believe that it depends on the processor architecture. When you say 128-bit computer, this may mean different things. There is no such thing as an "128 bit computer". The design may allow 128bit core (processor) in which case an int most likely be 128bit. Or it may imply that only the bus is 128 bit. Or both. One may assume that on the 128bit Intel processor when it becomes available , the size of an integer data type will be 128bit IF it has an 128bit core, and not just the bus.
I think you can use 'printf' like blew, int printf( const char *format [, argument]... );int _printf_l( const char *format, locale_t locale [, argument]... );int wprintf( const wchar_t *format [, argument]... );int _wprintf_l( const wchar_t *format, locale_t locale [, argument]... );at the same time, I give a example using the 'printf',/** * example using the 'printf' */include int main() { int e; int i; e = _set_printf_count_output( 1 ); printf( "%%n support was %sabled.\n", e ? "en" : "dis" ); printf( "%%n support is now %sabled.\n", _get_printf_count_output() ? "en" : "dis" ); printf( "12345%n6789\n", &i ); // %n format should set i to 5 printf( "i = %d\n", i ); }
The function textattr in conio.h can be use for this purpose a small program has presented here... #include<conio.h> int main() { textattr(129); cprintf("My name is Lord Blade..."); return 0; } here in the textattr till 128 only colors would be set and more than it colors with blink.
A Mage is ver good ( if you know a good build) for example 3 rec 6 int until level 25 then full int.
Ah, honey, in C, you can get the number of elements in an array by dividing the total size of the array by the size of one element. So, if you have an array of integers, you can do something like int size = sizeof(array) / sizeof(array[0]); and voilà, you've got the number of elements. Just be careful with those pesky pointers and make sure you're not trying to count elements in a pointer instead of an actual array.
To print the desired format in a program, you can use a loop to iterate through the characters of the word "computer" and print substrings of increasing length. Here is a simple Python program to achieve this: word = "computer" for i in range(1, len(word) + 1): print(word[:i]) This program will output the desired format: c co com comp compu comput compute computer
It is 'long long int' meaning 64 bit (8 byte).
16 bit and 32 bit are the most common values. See sizeof.
#include<iostream> #include<time.h> #include<iomanip> #include<string> void swap(int& x, int& y) { x^=y^=x^=y; } void bubble_sort(int* A, int size) { while(size) { int n=0; for(int i=1; i<size; ++i) { if(A[i-1]>A[i]) { swap(A[i-1], A[i]); n=i; } } size=n; } } void insertion_sort(int* A, int size) { for(int i=1; i<size; ++i) { int value=A[i]; int hole=i; while( hole && value<A[hole-1] ) { A[hole]=A[hole-1]; --hole; } A[hole]=value; } } void selection_sort(int* A, int size) { for(int i=0; i<size-1; ++i) { int j=i; for(int k=i+1; k<size; ++k) if(A[k]<A[j]) j=k; if( i!=j ) swap(A[i],A[j]); } } void sort(int* A, int size, int sort_type) { switch(sort_type) { case(0): bubble_sort( A, size ); case(1): insertion_sort( A, size ); case(2): selection_sort( A, size ); } } int* copy_array(int* A, int size) { int* copy=new int[size]; memcpy(copy, A, size*sizeof(int)); return(copy); } void print_array(int* A, int size, char* prompt) { std::cout<<prompt<<"\t"; for(int i=0; i<size; ++i) std::cout<<std::setw(2)<<A[i]<<" "; std::cout<<std::endl; } int get_rand(int range_min=0, int range_max=RAND_MAX) { return((int) ((double)rand() / (RAND_MAX + 1) * ((range_max + 1) - range_min) + range_min)); } int input_char(std::string prompt, std::string input) { char ch; do { std::cout<<prompt<<": "; std::cin>>ch; } while(input.find(ch)==std::string::npos); return(input.find(ch)%(input.size()/2)); } int main() { srand((unsigned) time(NULL)); int size = get_rand( 10, 80); if( int* A = new int[size] ) { for( int i=0; i<size; ++i ) A[i]=get_rand( 1, size ); int choice=input_char("Please select a sorting method:\n[B]ubble, [I]nsert, [S]election", "bisBIS"); std::cout<<"You chose "; switch(choice) { case(0): std::cout<<"bubble"; break; case(1): std::cout<<"insertion"; break; case(2): std::cout<<"selection"; break; } std::cout<<" sort...\n"<<std::endl; print_array( A, size, "Before sorting" ); sort(A, size, choice); print_array( A, size, "After sorting" ); delete [] A; } return(0); }
printf ("sizeof (int) = %d\n", (int)sizeof (int));
"int" is the abbreviation for an integer data type. In Java an int is specifically a 32-bit signed integer.
A Java program should run on any platform (hardware + operating system) for which a JVM (Java Virtual Machine) is installed. Unlike the "C" language, the size of data items in Java does not depend on the platform; for example, an int will always have a size of 32 bits, no matter how the underlying computer hardware is organized.A Java program should run on any platform (hardware + operating system) for which a JVM (Java Virtual Machine) is installed. Unlike the "C" language, the size of data items in Java does not depend on the platform; for example, an int will always have a size of 32 bits, no matter how the underlying computer hardware is organized.A Java program should run on any platform (hardware + operating system) for which a JVM (Java Virtual Machine) is installed. Unlike the "C" language, the size of data items in Java does not depend on the platform; for example, an int will always have a size of 32 bits, no matter how the underlying computer hardware is organized.A Java program should run on any platform (hardware + operating system) for which a JVM (Java Virtual Machine) is installed. Unlike the "C" language, the size of data items in Java does not depend on the platform; for example, an int will always have a size of 32 bits, no matter how the underlying computer hardware is organized.
The maximum size of an array in C++ is the same as the maximum number that can be represented by an int (usually 2,147,483,647 elements, or just over 2 billion). An int is defined as being dependent on a CPU's architecture, so the 2 billion number is based on 32-bit compilation. Some 64-bit processors also compile to a 32-bit int, and would be limited to just over 2 billion elements. Available memory is also a consideration on the maximum size of an array. The larger the elements, the fewer elements you can achieve. This is unlikely to be a problem on 64-bit systems, but on 32-bit systems it could be.
The maximum size of INT is 1. If you go over then it will be an error.
sizeof (long int) usually 4 or 8
#include<iostream> void insertion_sort(int* a,int len) { for(int i=1; i<len; ++i) { int* hole=a+i; int* prev=hole-1; int cur=*hole; while(hole!=a && cur<*(prev)) { *(hole)=*(prev); --hole, --prev; } *hole=cur; } } void print_array(int* a,int len) { for(int i=0; i<len; ++i) std::cout<<a[i]<<" "; std::cout<<std::endl; } int main() { int a[]={9,1,8,3,7,2,5,4,6}; int size=sizeof(a)/sizeof(a[0]); std::cout<<"Before:\t"; print_array(a,size); insertion_sort(a,size); std::cout<<"After:\t"; print_array(a,size); return(0); }
int myvar; printf ("size of myvar is %d\n", (int)sizeof (myvar));
printf ("sizeof (int) is %d bytes", (int)sizeof (int)); Most likely it will be 2 or 4.