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172.16.0.0 is really a B Class address with 16 network bits and 16 host bits, i.e. Network Address 172.16.0.0 has 255.5255.0.0 as Subnet mask in Classful Addressing. To create 32 (25) subnets we will use first five bits for Network part and will leave 3 bits as Host bits in third octet. Now Addressing will be:Network Address: 172.16.0.0\21 or 172.16.0.0 Subnet Mask: 255.255.248.0First two networks will be : (1) 172.16.0.0-172.16.7.255\21, (2) 172.16.8.0-172.16.15.255\21 and last two networks will be (1) 172.16.240.0-172.16.247.255\21, (2) 172.16.248.0-172.16.255.255\21.(Note to use Zero subnet - remember to use IP SUBNET ZERO command.)
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172.16.0.0 is really a B Class address with 16 network bits and 16 host bits, i.e. Network Address 172.16.0.0 has 255.5255.0.0 as Subnet mask in Classful Addressing. To create 32 (25) subnets we will use first five bits for Network part and will leave 3 bits as Host bits in third octet. Now Addressing will be:Network Address: 172.16.0.0\21 or 172.16.0.0 Subnet Mask: 255.255.248.0First two networks will be : (1) 172.16.0.0-172.16.7.255\21, (2) 172.16.8.0-172.16.15.255\21 and last two networks will be (1) 172.16.240.0-172.16.247.255\21, (2) 172.16.248.0-172.16.255.255\21.(Note to use Zero subnet - remember to use IP SUBNET ZERO command.)
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2046 Breakdown: 11111111.11111111.11111000.00000000 /21 - 21 bits in network address represented by ones in binary address above. Leaves 2^11th power host addresses left (the zeros to the right). Equals 2048 host addresses minus the two reserved addresses = 2046
Each bit allows 21 combinations. Accordingly, n number of bits provide 2n combinations.Therefore, 5 bits provide 25 = 32 combinations. # 00001 # 00010 # 00011 # 00100 # 00101 # 00110 # 00111 # ...
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