1 gram of water is exactly one mililiter.
the weight of the displaced water is equal to the weight of the object
D = M/V density = mass/volume to solve for one unknown, you need two knowns...so if you know the density and volume, you can calculate weight. the density of water is 1ish, so in that case the weight would be equal to the volume.
This is the specific gravity of the mineral. It's a comparison of how much mass a given volume of it has compared to the mass of an equal volume of water.
Specific gravity
Specific gravity
How much weight a boat will hold depends on the volume of the boat. This is called displacement. displacement is exactly equal to the weight of the water the boat displaces, that is the boat makes a hole in the water. The volume of that hole times the weight of water (64 lbs for salt water, 62.4 for fresh water) - displacement. The volume of water displaces is equal to the volume of the boat.
Yes, according to Archimedes' principle, when an object floats in a fluid, the weight of the object is equal to the weight of the fluid it displaces. This means that the volume of the displaced water is equal to the volume of the object.
Specific gravity.
The volume of water displaced is equal to the volume of the object submerged in water. This is known as Archimedes' principle, which states that the buoyant force acting on an object is equal to the weight of the water displaced by the object.
This statement is not correct. The weight of the water displaced by a body in it, is equal to the buoyancy force that the body will experience. In the case the body floats on the surface of water, the weight of the water displaced by the body is equal to the weight of the body.
That completely depends on the object's volume (which you have not mentioned). The buoyant force on it is equal to the weight of an equal volume of water.
Compare its weight to the weight of an equal volume of water. The weight of the specimen divided by the weight of the water equals the density of the specimen.