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Specific gravity

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Sigurd Nolan

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3y ago

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Is Hardness or Specific gravity compares the weight of a mineral with the weight of an equal amount of water?

Hardness compares the weight of a mineral with the weight of an equal amount of water


What compares the weight of a mineral with the weight of an equal amount of water?

Specific gravity compares the weight of a mineral with the weight of an equal amount of water! :D


What compare the weight of a mineral with the weight of an equal amount of water?

Specific gravity compares the weight of a mineral with the weight of an equal amount of water! :D


What compares weight of minerals with weight of an equal volume of water?

Specific gravity


Compares weight of minerals with weight of an equal volume of water called?

The weight of a mineral is compared to the weight of an equal volume of water using a measurement called specific gravity. Specific gravity is the ratio of the weight of the mineral to the weight of an equal volume of water. Minerals with a specific gravity greater than 1 are heavier than water, while those with a specific gravity less than 1 are lighter.


This is expressed as the weight of a mineral compared with the weight of an equal volume of water?

This is the specific gravity of the mineral. It's a comparison of how much mass a given volume of it has compared to the mass of an equal volume of water.


How heavy or dense a rock is what is it called?

The heaviness or density of a rock is referred to as its specific gravity, which compares the weight of the rock to the weight of an equal volume of water. It is a measure of how compact the material in the rock is.


How do you get the specific gravity of a mineral?

Fill a beaker with water, and weigh it. Weigh a sample of the mineral. That's the mass of the mineral. Put the sample in the beaker and weigh that. The weight of the water-filled beaker plus the weight of the mineral sample will be greater than the weight of the beaker with mineral sample and water. The difference is the weight of the displaced water, in grams. The volume of the mineral sample, in cubic centimeters is equal to the weight of the displaced water, in grams. Calculate the specific gravity of the mineral by dividing the weight of the mineral sample by the volume of the mineral sample. Example: your beaker weighs 40 grams. Filled with water, it's 1040 grams. The sample of mineral weighs 160 grams. The beaker with the sample of mineral and water weighs 1179.7 grams. The mineral, and the beaker with water would have a combined weight of 1200 grams, but the beaker with mineral and water weighs 20.3 grams less than that, so the mineral sample is displacing 20.3 cubic centimeters of water. Given a mass of 160 grams and a volume of 2.03 CC, the specific gravity would be found by dividing 160 by 20.3. It's 7.85. (Which happens to be the specific gravity of some iron.)


How do you calculate the the specific gravity for minerals?

Specific gravity of a mineral is calculated by dividing the weight of the mineral by the weight of an equal volume of water. This is typically done using a balance to measure the weight of the mineral and a graduated cylinder to measure water displacement. The specific gravity value provides information about the density and composition of the mineral in comparison to water.


The density of a pure mineral?

The density of a pure mineral is measured using various apparatus and techniques which are covered in most mineralogy textbooks.


Is the weight of a submerged object equal to the weight of the displaced fluid?

No, it is equal in volume.


How does finding the volume of the water that was displaced help you find the volume of the mineral itself?

Finding the volume of water displaced by a mineral allows you to determine the mineral's volume based on Archimedes' principle. When the mineral is submerged in water, the volume of water displaced is equal to the volume of the mineral itself. By measuring the displaced water accurately, you can calculate the mineral’s volume without directly measuring its dimensions, which is particularly useful for irregularly shaped objects. This method provides a straightforward way to assess the mineral's volume in a practical setting.