0
What else can I help you with?
How do you calculate the number of moles of NaI in 50.0mL of a 0.400M solution?
To calculate the number of moles of NaI in 50.0mL of a 0.400M solution, you first need to convert the volume to liters by dividing by 1000 (since 1L = 1000mL). Then, use the formula moles = Molarity x Volume (in liters) to find the number of moles of NaI. In this case, it would be 0.400 mol/L x 0.050 L = 0.020 moles of NaI.
.05l equals how many ml?
1 litre = 1000 millilitres. You now have all the information required to answer this and similar questions.
How many runways does gatwick have?
Manchester Airport (MAN/EGCC) in the UK has 2 runways: 05L/23R - this is the original runway 05R/23L - this runway is the airport's 2nd runway and was opened in 2001 Runway numbers correspond to their magnetic headings to the nearest 10 degrees (so runway 23 faces approximately 230 degrees magnetic). Due to the nature of constantly changing magnetic variation runways occasionally require re-designating. As a result of this on 07/06/2007 Manchester re-designated their runways from 06L/24R and 06R/24L to 05L/23R and 05R/23L.
How many moles of HCL in 50ml of 1.0 M HCL?
50ml = .05L of HCL 1.0 M = 1mol / 1L of HCL simply multiply - .05 by 1.0, and get your answer!
A buffer is prepared by mixing 50.0 ml of 0.050 m sodium bicarbonate and 10.7 ml of 0.10 m naoh what is the pH for carbonic acid ka1 equals 4.5 x 10 -7 and ka2 equals 4.7 x 10 -11?
0.050M x .05L = .0025 mol NaHCO3 0.10M x .0107L = .00107 mol NaOH Excess NaHCO3 = .0025-.00107 = 0.00143 pH = pKa2 + log(.00107/.00143) pH = 10.20
50 ml of point05M HCl to 150 ml of point10 M HNO3 what are the concentrations of all species in this solution?
I'll assume when you say species, you are referring to the ions of each compound, so we are looking for the concentration of H+, Cl-, and NO3-.To begin, we have 0.2L of total solution (.05L HCl + .15L HNO3).I'll do Cl- first: You have .05L of 0.05mol/L HCl. H and Cl are in 1:1 ratio, so you can say you have 0.05L of 0.05mol/L Cl-.0.05L * 0.05mol/L=0.0025mol Cl- divide this by the total volume, 0.0025 mol/.200L=0.0125M Cl-NO3-: .150L*0.1M NO3-= 0.015mol NO3-/0.200L=0.075M NO3-H+ occurs in both acids so you have to add both amounts to find the concentrations. We know that for HCl, H has a 1:1 ratio with Cl, so if there is 0.0025mol Cl- there must be 0.0025mol of H+.Same with HNO3, there must be 0.015mol H+.Add these together: 0.0025mol+0.015mol= 0.0175mol H+ in total.Divide by the total volume to get concentration: 0.0175mol/.200L= 0.0875M H+
