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How many btus are required to change one pound of ice at 20 f to steam at 220 f?
It takes approximately 144 BTUs to change one pound of ice at 20°F to water at 212°F, and an additional 970 BTUs to change the water to steam at 220°F, for a total of 1114 BTUs.
How many btus are required to change 5 pound of ice at 20 degrees Fahrenheit to steam at 220 degrees Fahrenheit?
To change 5 pounds of ice at 20°F to steam at 220°F, you will need to go through multiple phases: raise ice temperature to 32°F, melt ice to water at 32°F, raise water temperature to 212°F, and then convert water to steam at 212°F to steam at 220°F. The total heat required, in BTUs, is around 503 BTUs per pound of ice, which translates to about 2515 BTUs for 5 pounds of ice.
How many btus are required to change five pounds of ice at 20 degrees to steam at 220 degrees?
6,520 Btus
How many btus are required to convert 1lb ice to 1lb water?
To convert 1 pound of ice at 32°F to 1 pound of water at 32°F, you need to supply 144 BTUs. This energy is required to overcome the latent heat of fusion, which is the energy needed to change ice into water without changing its temperature.
How many BTU will it take to change 10 pounds of ice at 20 degrees to steam at 220 degrees?
To change 10 pounds of ice at 20 degrees Fahrenheit to steam at 220 degrees Fahrenheit, you need to supply enough energy to first melt the ice, then heat the water to the boiling point, and finally convert it to steam. This process requires approximately 180 BTUs per pound of ice to melt it, 180 BTUs per pound of water to heat it to the boiling point, and then 970 BTUs per pound of water to convert it to steam. So, for 10 pounds of ice, the total BTUs required would be around 18,300 BTUs.
How many Btus must be removed from one pound of water at 200f fro it to end up as ice at 30f?
To determine the BTUs that must be removed from one pound of water at 200°F to convert it to ice at 30°F, we need to account for several steps: cooling the water from 200°F to 32°F (the freezing point), the phase change from water to ice at 32°F, and then cooling the ice from 32°F to 30°F. Cooling the water from 200°F to 32°F requires about 168 BTUs (1 BTU cools 1 pound of water by 1°F). Freezing the water at 32°F requires the removal of 80 BTUs (latent heat of fusion). Cooling the ice from 32°F to 30°F requires an additional 2 BTUs. In total, approximately 250 BTUs must be removed (168 + 80 + 2 = 250 BTUs).
How many btus will it take to raise 50 pounds of ice at 32 degrees to water at 160 degrees?
To raise 1 pound of ice from 32°F to water at 32°F it requires 144 BTUs. Since you have 50 pounds of ice, you would need 50 * 144 BTUs to raise the ice to water at 32°F. To further raise the water from 32°F to 160°F, you would need an additional amount of BTUs based on the specific heat capacity of water.
How many Btu's are required to change one pound of ice at 20 F to steam at 220 F?
To change one pound of ice at 20°F to steam at 220°F, you need to consider two processes: heating the ice to 32°F, melting the ice at 32°F, heating the water to 212°F, and finally boiling the water to steam at 220°F. The total number of BTUs required for this process is around 1440 BTUs.
How many btus must be removed from one pound of water at 200 for it to end up as ice at 30?
144
If one pound of water is at a temperature of 32 degrees Fahrenheit, how many BTU’s must be removed in order to create a block of ice at 17 degrees?
LATENT HEAT OF FUSION When one pound of ice melts, it absorbs 144 BTUs at a constant temperature of 32°F. If one pound of water is to be frozen into ice, 144 BTUs must be removed from the water at a constant temperature of 32°F.
How many btu's must be removed from one pound of water at 200f for it to end up as ice at 30f?
To convert water at 200°F to ice at 30°F, you need to remove 1 BTU to cool water from 200°F to 32°F to become ice. Then, you need to remove 144 BTUs to cool the ice from 32°F to 30°F. So, total BTUs needed to remove from one pound of water at 200°F to end up as ice at 30°F is 144 + 1 = 145 BTUs.
How many Btus must be removed from 1lb of water at 200F for it end up as ice at 30F?
To convert 1 lb of water at 200°F to ice at 30°F, you need to remove 233 BTUs. This involves cooling the water from 200°F to 32°F (latent heat of fusion) and then further cooling the ice from 32°F to 30°F.
