If 12,000 btuh = 1 ton cooling = 2000 pounds ice; then 12 btuh will melt 2 pounds of ice to water.
To melt 1 ton (2000 pounds) of ice, it would require approximately 288,000 BTU/hr of energy. This is because it takes 144 BTU to melt one pound of ice, and 2000 pounds x 144 BTU = 288,000 BTU.
To calculate the BTUs required to raise the temperature of water, you can use the formula: BTUs = (pounds of water) x (temperature change in °F) x (1 BTU). For 15 pounds of water going from 100°F to 120°F, the calculation would be: BTUs = 15 pounds x 20°F x 1 BTU = 300 BTUs.
To calculate the heat required to raise the temperature of water, you can use the formula: Q = m * c * ΔT, where Q is the heat energy, m is the mass of water, c is the specific heat capacity of water, and ΔT is the change in temperature. For 5 pounds of water, you'd convert that to approximately 2268 grams. The specific heat capacity of water is 4.186 J/g°C. Considering the conversion factor for BTU to J (1 BTU = 1055.06 J), you'd then convert the result to BTU, which comes out to approximately 1.53 BTU.
To melt 60 lbs of lead, approximately 25,200 BTU of heat energy is required. Lead has a melting point of 621.5°F and a specific heat capacity of 0.031 BTU/lb°F. Multiplying these values gives the total heat energy needed for melting.
It takes about 144 BTUs to melt 1 pound of ice at its melting point of 32°F (0°C) and fully convert it into water at the same temperature.
To melt 1 ton (2000 pounds) of ice, it would require approximately 288,000 BTU/hr of energy. This is because it takes 144 BTU to melt one pound of ice, and 2000 pounds x 144 BTU = 288,000 BTU.
It would take approximately 12,000 BTU (British Thermal Units) to melt one ton (2000 pounds) of ice in 24 hours. This is based on the heat of fusion of ice, which is 144 BTU per pound.
10 x (70 - 50) = 200 Btu
212-65=147. 147(20)=2940 btu needed is this right?
1 BTU is required to raise 1lb of water 1 degree F in 1 hour. 212-75=137 degrees 600 lbs water x 137 degrees= 82,200 BTU's required to change 75 degree water to 212 degree water. To change 212 degree water to 212 degree steam it requires 970 btu's (latent heat of vaporization) per lb of water 970 btu x 600 lbs water = 582,000 btu Answer - 582,000 btu+ 82,200 btu = 664,200 btu's
135 btu
To calculate the BTUs required to raise the temperature of water, you can use the formula: BTUs = (pounds of water) x (temperature change in °F) x (1 BTU). For 15 pounds of water going from 100°F to 120°F, the calculation would be: BTUs = 15 pounds x 20°F x 1 BTU = 300 BTUs.
32 BTU = 24,901.416 foot-pounds.
To calculate the heat required to raise the temperature of water, you can use the formula: Q = m * c * ΔT, where Q is the heat energy, m is the mass of water, c is the specific heat capacity of water, and ΔT is the change in temperature. For 5 pounds of water, you'd convert that to approximately 2268 grams. The specific heat capacity of water is 4.186 J/g°C. Considering the conversion factor for BTU to J (1 BTU = 1055.06 J), you'd then convert the result to BTU, which comes out to approximately 1.53 BTU.
There are no BTUs in an office water-cooler. But you can calculate how many BTUs are removed by the cooler. One BTU or British Thermal Unit is the amount of heat energy required to raise the temperature of one pound of water one degree Fahrenheit. There for when you remove one BTU you are lowering one pound of water one degree Fahrenheit. So if you know how many pounds of water you have and the temperature of the water you start with and the temperature of the water comming out of the cooler you can calculate how many BTUs the cooling unit of the water cooler has removed. BTU=Temp1 - Temp 2 X LB water
To evaporate one gallon of water, approximately 1,200 British thermal units (Btu) are required. This is based on the latent heat of vaporization, which is the amount of energy needed to convert water from liquid to vapor without changing its temperature. Specifically, it takes about 970 Btu to vaporize one pound of water, and since one gallon of water weighs about 8.34 pounds, the total comes to around 1,200 Btu.
To calculate the BTU needed to heat 10 gallons of water from 32°F to 212°F, you can use the formula: BTU = gallons × 8.34 (weight of water per gallon in pounds) × temperature change (in °F). The temperature change is 212°F - 32°F = 180°F. Thus, BTU = 10 gallons × 8.34 lbs/gallon × 180°F = 15,012 BTU.