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To calculate the BTU needed to heat 10 gallons of water from 32°F to 212°F, you can use the formula: BTU = gallons × 8.34 (weight of water per gallon in pounds) × temperature change (in °F). The temperature change is 212°F - 32°F = 180°F. Thus, BTU = 10 gallons × 8.34 lbs/gallon × 180°F = 15,012 BTU.
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Five pounds sea water at 32F are heated until the temperature reaches 212F what will be the amount of BTU required?
To calculate the amount of BTU required to heat the sea water from 32F to 212F, you can use the specific heat capacity of water (1 BTU/lb°F). The change in temperature is 212F - 32F = 180F. So, the amount of BTU required would be 5 lbs * 180°F * 1 BTU/lb°F = 900 BTU.
Does liquid water turns into a solid at 100 Fahrenheit?
No, water turns into a solid at 32 degrees Fahrenheit, not 100 degrees Fahrenheit. 100 degrees Fahrenheit is the temperature at which water boils and turns into a gas.
What are the three temperature systems?
There's really only one scientific measurement for temperature, and that's the Kelvin scale. The commonly used systems for weather are Celsius and Fahrenheit. Water freezes at 273K, 0C, and 32F. Water boils at 373K, 100C, and 212F.
How many btus are required to change one pound of ice at 20 degree Fahrenheit to steam at 220 degree Fahrenheit?
1)This is a 5 part question. The first is realizing that 20F to 32F uses .5BTU per pound per degree. That means it takes 32-20=12*.5=6BTUs to get the ice to 32F. 2)Then you need to know the Latent Heat of Fusion for Ice which is 144BTUs (given). Lets assumes the ice changes from ice to water instantaneously at 32F. 3)Next we calculate the BTUs from 32F to 212F. Which is 1BTU per pound per degree F. 212-32=180 so it take 180BTUS. 4)Next we have to use the Latent Heat of Vaporization of water which will say instantaneously converts water to vapor. This takes 970BTUS (given). 5)Then we calculate the BTUS from 212F to 220F. Which is .5BTUs per pound per degree F which is 220-212=8*.5=4BTUs...... Finally add up all the BTUs and you get 6+144+180+970+4=1304BTUs.
How many BTU are required to change one pound of ice at 20 degrees Fahrenheit to steam at 220 degrees Fahrenheit?
1)This is a 5 part question. The first is realizing that 20F to 32F uses .5BTU per pound per degree. That means it takes 32-20=12*.5=6BTUs to get the ice to 32F. 2)Then you need to know the Latent Heat of Fusion for Ice which is 144BTUs (given). Lets assumes the ice changes from ice to water instantaneously at 32F. 3)Next we calculate the BTUs from 32F to 212F. Which is 1BTU per pound per degree F. 212-32=180 so it take 180BTUS. 4)Next we have to use the Latent Heat of Vaporization of water which will say instantaneously converts water to vapor. This takes 970BTUS (given). 5)Then we calculate the BTUS from 212F to 220F. Which is .5BTUs per pound per degree F which is 220-212=8*.5=4BTUs...... Finally add up all the BTUs and you get 6+144+180+970+4=1304BTUs.
What temperature does it need for life to live?
That depends on the organism you're talking about. In general though, life as we know it needs liquid water to survive. That would suggest that the temperature range would fall somewhere around 32F and 212F give or take several degrees depending on a number of variables.
60 degrees celsius is how many degrees Fahrenheit?
Start by taking the number in Fahrenheit and subtracting 32. Then divide the number by 9, and then multiply it by 5. This is how you convert Fahrenheit to Celsius or use the equation C = (F - 32) × 5/9In this case, the answer is about 15.56 degrees Celsius.
What is the freezing point of water in degrees?
It is 0C and 32F.
What temperature is halfway between 32F 212F?
122 degrees F 212-32=180 180 divided by 2= 90 90+32= 122 I am just guessing. It's what my friend told me
What is the temperature in degrees Celsius that water is frozen?
water freezes at 0C or 32F
How can the RTD be calibrated without using a comparison thermometer?
A fairly accurate two-point calibration (if the sensing element is submersible) can be achieved by using an ice-water-salt solution to calibrate to 32F, and using boiling water to calibrate to 212F (corrected for atmospheric pressure at your location). If you live in a metric part of the world, your calibration points would be 0C and 100C, of course.
How many BTUs will it take to change 1 gallon of water at 32 degrees to ice at 32 degrees?
You would need to remove approximately 1200 BTUs of heat to convert a gallon of water to ice. There are 8.34 lb in a gallon of water, which converting to lb-moles is 0.463. The latent heat of crystallization for water is -2583.4 BTU/lb-mole. Multiplying the two together and you get -1197 BTUs, which means you need to remove that amount of heat to convert the gallon of water to ice.
