0
What else can I help you with?
How many btus are required to change one pound of ice at 20 f to steam at 220 f?
It takes approximately 144 BTUs to change one pound of ice at 20°F to water at 212°F, and an additional 970 BTUs to change the water to steam at 220°F, for a total of 1114 BTUs.
How many BTUS in 1 pound of steam at 212 degrees Fahrenheit?
One pound of steam at 212 degrees Fahrenheit contains 1150 BTUs of energy.
How many btu's must be removed from one pound of water at 200f for it to end up as ice at 30f?
To convert water at 200°F to ice at 30°F, you need to remove 1 BTU to cool water from 200°F to 32°F to become ice. Then, you need to remove 144 BTUs to cool the ice from 32°F to 30°F. So, total BTUs needed to remove from one pound of water at 200°F to end up as ice at 30°F is 144 + 1 = 145 BTUs.
How many Btu's are required to change one pound of ice at 20 F to steam at 220 F?
To change one pound of ice at 20°F to steam at 220°F, you need to consider two processes: heating the ice to 32°F, melting the ice at 32°F, heating the water to 212°F, and finally boiling the water to steam at 220°F. The total number of BTUs required for this process is around 1440 BTUs.
How many btus does it take to turn water into steam?
It takes approximately 970 BTUs to convert one pound of water at 212°F (100°C) to steam at the same temperature.
How many btus are required to change one pound of ice at 20 f to steam at 220 f?
It takes approximately 144 BTUs to change one pound of ice at 20°F to water at 212°F, and an additional 970 BTUs to change the water to steam at 220°F, for a total of 1114 BTUs.
If one pound of water is at a temperature of 32 degrees Fahrenheit, how many BTU’s must be removed in order to create a block of ice at 17 degrees?
LATENT HEAT OF FUSION When one pound of ice melts, it absorbs 144 BTUs at a constant temperature of 32°F. If one pound of water is to be frozen into ice, 144 BTUs must be removed from the water at a constant temperature of 32°F.
How many btus must be removed from one pound of water at 200 for it to end up as ice at 30?
144
BTUs to melt one pound of ice?
From high school science class; it takes 144 BTUs to melt a pound of ice. That takes it to 32 degrees F. To then raise the temp to 72 deg., would take about 40 more BTUs.
How many BTUs must be removed from one pound of water at 200 F for it to end up as ice at 30 F?
actually its 313.
How many BTUS in 1 pound of steam at 212 degrees Fahrenheit?
One pound of steam at 212 degrees Fahrenheit contains 1150 BTUs of energy.
How many btus must be removed from one pound of water at 200 degrees f for it to end up as ice at 30 degrees f?
313 Btu
How many btu's must be removed from one pound of water at 200f for it to end up as ice at 30f?
To convert water at 200°F to ice at 30°F, you need to remove 1 BTU to cool water from 200°F to 32°F to become ice. Then, you need to remove 144 BTUs to cool the ice from 32°F to 30°F. So, total BTUs needed to remove from one pound of water at 200°F to end up as ice at 30°F is 144 + 1 = 145 BTUs.
How many Btu's are required to change one pound of ice at 20 F to steam at 220 F?
To change one pound of ice at 20°F to steam at 220°F, you need to consider two processes: heating the ice to 32°F, melting the ice at 32°F, heating the water to 212°F, and finally boiling the water to steam at 220°F. The total number of BTUs required for this process is around 1440 BTUs.
How many btus does it take to turn water into steam?
It takes approximately 970 BTUs to convert one pound of water at 212°F (100°C) to steam at the same temperature.
How many btus does it take to raise half pound of water 1 degree?
One BTU is the energy required to raise one pound of water by one degrees. Therefore, your answer would be one half.
How many BTU's must be removed from one pound of water at 200 degrees for it to end up as ice at 30 degrees F?
To calculate the BTUs needed to convert one pound of water at 200°F to ice at 30°F, we must consider two stages: first, cooling the water from 200°F to 32°F, and then freezing it to ice at 32°F, and finally cooling the ice to 30°F. Cooling from 200°F to 32°F requires removing about 168 BTUs (using the specific heat of water, which is approximately 1 BTU/lb°F). Freezing the water at 32°F to ice requires removing 80 BTUs (the latent heat of fusion). Finally, cooling the ice from 32°F to 30°F requires an additional 2 BTUs (using the specific heat of ice, which is about 0.5 BTU/lb°F). Adding these together: 168 + 80 + 2 = 250 BTUs must be removed.
