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To calculate the BTUs needed to convert one pound of water at 200°F to ice at 30°F, we must consider two stages: first, cooling the water from 200°F to 32°F, and then freezing it to ice at 32°F, and finally cooling the ice to 30°F.

  1. Cooling from 200°F to 32°F requires removing about 168 BTUs (using the specific heat of water, which is approximately 1 BTU/lb°F).
  2. Freezing the water at 32°F to ice requires removing 80 BTUs (the latent heat of fusion).
  3. Finally, cooling the ice from 32°F to 30°F requires an additional 2 BTUs (using the specific heat of ice, which is about 0.5 BTU/lb°F).

Adding these together: 168 + 80 + 2 = 250 BTUs must be removed.

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3mo ago

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How many btus must be removed from one pound of water at 200 degrees f for it to end up as ice at 30 degrees f?

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