00 to 0F represents 16 addresses Binary representation is 1111 therefore you need 4 address lines to connect to all addresses
In the 2k*16 , the 11 address lines are required and the 16 input-output lines are required..
How many no of address lines required in 1MB memory 11,16,22 or 24 u haven't specified correct options! 20 address lines will be required because 1 MB is 1024 KB that is 1024*1024 Byte which is equivalent to (2^10)^2 bytes if ur memory is Byte addressable then address lines required will be 20.
A 2K X 8 memory requires 11 address lines and 8 data lines
17 address lines and 8 data lines. 2^17=128k
To determine the number of address lines required for 1 GB of memory, we can use the formula (2^n = \text{Memory Size}), where (n) is the number of address lines. Since 1 GB equals (2^{30}) bytes, we need (30) address lines to uniquely address each byte in 1 GB of memory. Therefore, (30) address lines are required for 1 GB.
2kb=2*1024=2048 2^11=2048 therefore 11 address lines are required
The number of address lines needed to access N-KB is given by log2N Then the number of address lines needed to access 256KB of main memory will be log2256000=18 address lines.
10. 210 = 1024.
It takes 23 address lines to address 8 mb of memory.
To calculate the number of address lines required for a 64 kB memory, first convert 64 kB into bytes: 64 kB = 64 × 1024 bytes = 65,536 bytes. The number of address lines needed can be determined using the formula (2^n = \text{total number of addresses}), where (n) is the number of address lines. Since 65,536 is (2^{16}), you need 16 address lines to address a 64 kB memory.
There are 24 address lines required for 16 mb. That covers 12 mb. The next step down is 23 address lines, which is 8 mb. The 8085 and 8086/8088 cannot address 12 mb. Only the 80286 and higher can.
Microprocessor has 16 address lines and microcontroller has 20 address lines