0
The number of bits in data and address inputs of memory varies depending on the architecture of the system. Commonly, modern systems use 32-bit or 64-bit architectures, meaning they can handle 32 or 64 bits of data at a time, respectively. The address input, which determines how much memory can be directly accessed, is often the same as the data bus width; for instance, a 64-bit architecture typically has a 64-bit address bus, allowing access to a larger memory space.
What else can I help you with?
Why 4 bit address bus is grounded?
The data bus in the 8086 is 16 bits in size, while the address bus is 20 (16bits would only address 64KB of memory, an extra 4 bits allows to address the total of 1MB, this is done trough segmentation of the memory). To form a multiplexed of data bus and address bus, four bits of 8086 address bus are grounded.
What is byte addressable memory?
a byte is abasic storage unit in memory. when application program instructions and data are transferd to memory from storage devices. byte addressable memory refers to memory address that is accessed one byte (8 bits) at a time as opposed to 2 byte(16 bits), 4 byte(32 bits) or 8 byte(64 bits) addressable memory.
What stores the data that the CPU actively uses?
The CPU registers. If the data is too large to physically store in a register, the register stores the memory address containing the data instead (usually a RAM address but could be any address in the physical address space, including ROM and graphic memory). On a 32-bit system, data registers need to be at least 32-bits long in order to store memory addresses.
What is the memory's addressibility?
HI I am Ahtarva,The addressibility is how many bits does that particular processor or micro-controller's architecture use to specify the address of a memory location in the memory. For example if someone say that addressibility is 8 bit then your memory address contains 8 bits and at maximum you have 2^8 different memory locations (or say memory addresses in your device). Here 2^8 is called Address space.
Which memory stores programs and data files?
All data is stored in the same memory locations being it permanent or temporary memory, programs and data are essentially the same thing . The way that the data is differentiated is by using memory locations assigned to data string or information. In other words different data location address's for different data bits. Hope i helped.
How many bits are there in a data link layer Ethernet address?
How many bits are there in a data link layer ethernet address?
What is an address buffer and a data buffer?
The contents of the stack pointer and program counter are loaded into the address buffer and address-data buffer. These buffers are then used to drive the external address bus and address-data bus. As the memory and I/O chips are connected to these buses, the CPU can exchange desired data to the memory and I/O chips. The address-data buffer is not only connected to the external data bus but also to the internal data bus which consists of 8-bits. The address data buffer can both send and receive data from internal data bus.
How many memory cells or latches for holding 1 bit each that are implemented in SRAM with 24 address lines and 16 data lines?
In SRAM, each address line can access one unique memory cell, and with 24 address lines, you can address (2^{24}) unique memory locations. Since each memory location holds 1 bit and you have 16 data lines, you are able to read or write 16 bits simultaneously. Therefore, the total number of memory cells for holding 1 bit each is (2^{24} = 16,777,216) bits.
If a memory had 16 bit address bus and a 32 bit data bus what is the largest size of the memory?
A memory with a 16 bit address bus can address 216 or 65536 distinct items. If each item is 32 bits in size, then the item is 4 bytes. The size of this memory is then 262144 bytes. (256Kb)
How many address bus and deta bus in 8085?
The 8085 microprocessor has a 16-bit address bus and an 8-bit data bus. This means it can address up to 2^16 (or 65,536) memory locations, while it can transfer 8 bits of data at a time. The combination of these buses allows the 8085 to efficiently access and process data from memory.
How many address lines and data lines are required from 256K 16 memory system?
In a 256K x 16 memory system, the memory has 256K (256 * 1024 = 262,144) addressable locations and each location holds 16 bits of data. To calculate the number of address lines needed, we find the base-2 logarithm of 256K, which is 18 (since 2^18 = 262,144). For the data lines, since each location holds 16 bits, 16 data lines are required. Thus, the system requires 18 address lines and 16 data lines.
What are the different parts of a microprocessor?
An address bus (that may be 8, 16 or 32 bits wide) that sends an address to memoryoA data bus (that may be 8, 16 or 32 bits wide) that can send data to memory or receive data from memoryoAn RD (read) and WR (write) line to tell the memory whether it wants to set or get the addressed locationoA clock line that lets a clock pulse sequence the processor
