The data bus in the 8086 is 16 bits in size, while the address bus is 20 (16bits would only address 64KB of memory, an extra 4 bits allows to address the total of 1MB, this is done trough segmentation of the memory). To form a multiplexed of data bus and address bus, four bits of 8086 address bus are grounded.
a byte is abasic storage unit in memory. when application program instructions and data are transferd to memory from storage devices. byte addressable memory refers to memory address that is accessed one byte (8 bits) at a time as opposed to 2 byte(16 bits), 4 byte(32 bits) or 8 byte(64 bits) addressable memory.
How many bits are there in a data link layer ethernet address?
The CPU registers. If the data is too large to physically store in a register, the register stores the memory address containing the data instead (usually a RAM address but could be any address in the physical address space, including ROM and graphic memory). On a 32-bit system, data registers need to be at least 32-bits long in order to store memory addresses.
All data is stored in the same memory locations being it permanent or temporary memory, programs and data are essentially the same thing . The way that the data is differentiated is by using memory locations assigned to data string or information. In other words different data location address's for different data bits. Hope i helped.
HI I am Ahtarva,The addressibility is how many bits does that particular processor or micro-controller's architecture use to specify the address of a memory location in the memory. For example if someone say that addressibility is 8 bit then your memory address contains 8 bits and at maximum you have 2^8 different memory locations (or say memory addresses in your device). Here 2^8 is called Address space.
The contents of the stack pointer and program counter are loaded into the address buffer and address-data buffer. These buffers are then used to drive the external address bus and address-data bus. As the memory and I/O chips are connected to these buses, the CPU can exchange desired data to the memory and I/O chips. The address-data buffer is not only connected to the external data bus but also to the internal data bus which consists of 8-bits. The address data buffer can both send and receive data from internal data bus.
A memory with a 16 bit address bus can address 216 or 65536 distinct items. If each item is 32 bits in size, then the item is 4 bytes. The size of this memory is then 262144 bytes. (256Kb)
it is when you put data in a form of structure on a memory disk or anything that inputs something.
In a 256K x 16 memory system, the memory has 256K (256 * 1024 = 262,144) addressable locations and each location holds 16 bits of data. To calculate the number of address lines needed, we find the base-2 logarithm of 256K, which is 18 (since 2^18 = 262,144). For the data lines, since each location holds 16 bits, 16 data lines are required. Thus, the system requires 18 address lines and 16 data lines.
An address bus (that may be 8, 16 or 32 bits wide) that sends an address to memoryoA data bus (that may be 8, 16 or 32 bits wide) that can send data to memory or receive data from memoryoAn RD (read) and WR (write) line to tell the memory whether it wants to set or get the addressed locationoA clock line that lets a clock pulse sequence the processor
A 16-bit uP operates on instructions and data in 16-bit quantities. Therefore the databus is 16-bits. A 16-bit uP may also operate on larger quantities of data, however multiple CPU registers must be concatenated in order to maintain the data element in the uP register space. The data is always delivered to the processor 16 bits at a time. The amount of memory which it can address is a separate issue---the address bus size is totally distinct from the data bus size. The data bus determines how much memory may be delivered to the uP per cycle. The address bus size determines how much physical memory may actually be accessed by the uP. Therefore it is variable depending on how much memory is available. Typical systems today have 32-bit address busses which limit addressable memory to 4Gigabytes. (2^32) = 4G.