When you convert this decimal number to the binary format, we have 111001001 that has 9 digits so 9bits is required to represent it in normal case. To convert decimals to binary visit http://acc6.its.brooklyn.cuny.edu/~gurwitz/core5/nav2tool.html
I get 36 .
minimum 17
28-bits
To determine how many bytes are needed to represent the number 2501, we first convert it to binary. The binary representation of 2501 is "10011100001," which requires 12 bits. Since one byte is 8 bits, you would need 2 bytes (16 bits) to store the value 2501.
Each letter of the alphabet, whether upper case or lower case, can be represented with 7 bits.
The number of bits required to represent an integer number depends on the size of the integer, there is no absolute answer. Generally speaking, a binary number made up of some number of bits can be considered to directly represent an integer number according to the rules of binary arithmetic. If you specify the question a little differently you can come up with a question that does have an absolute answer. For example, if you ask what range of integers can be represented by a binary number with N bits, the answer is exactly 0 to 2^N (ignoring alternate ways to characterize binary numbers such as signed two's complement). More specifically, an 8 bit binary number can represent the integers from 0 to 255. There is also another way to restate your original question. That would be to assume that you are asking how many bits (at a minimum) does it take to represent a particular integer. In that case, again assuming unsigned binary arithmetic, the answer would be found by determining the next higher power of two than the number in question and finding log base 2 of that number. For example, the minimum number of bits required to represent the integer 60 would be 6, where the next higher power of two than 60 is 64, and the log base 2 (simply the power to which 2 must be raised to arrive at the number) is 6. In theory, an infinite number of bits could represent an infinity of integers, but that is probably not really what you are asking.
It takes 10 bits.
It takes 7 digits.
Qubits and bits can not be described in terms of one another.
The number of bits in a sentence depends on several factors, including the length of the sentence and the encoding used for the characters. For example, in ASCII encoding, each character typically requires 7 or 8 bits, while in UTF-8 encoding, characters can take anywhere from 1 to 4 bytes (8 to 32 bits) depending on the character. To calculate the total bits in a sentence, multiply the number of characters (including spaces and punctuation) by the number of bits per character based on the encoding.
The minimum number of address lines required to address 4k of memory is 12.To reach this number, remember that each line has two possibilities and keep doubling as you count off. So one line can be used for two possibilities. Two lines represent four possibilities. Three represent eight. When you get to ten, you have 1024 possibilities. So double to 2048 at 11 and again to 4096 at 12. Or for the shortcut, if you take two to the 12th power, you get 4096.
In ASCII code, each letter, number or punctuation mark takes one byte, or 8 bits. That gives you 256 discrete combinations. Two letters take 2 bytes, or 16 bits.