To represent -5 in binary using two's complement, you first need to determine how many bits are required for the positive equivalent, which is 5. In binary, 5 is represented as 101. To accommodate the negative sign, you typically use at least 8 bits for clarity, which would represent -5 as 11111011 in two's complement. Therefore, at least 8 bits are needed to represent -5 in this format.
23 can be represented in binary as 10111 and would therefore require 5 bits to represent.
40 bits or 5 byrtes
5 bits
32 values. 2^5=32
5
4 as to represent 10 we require 4 bits
5 bits, since 2 to the power 5 equals 32.
Well, honey, to represent months of the year, you need at least 4 bits because you've got 12 months in a year, and you need 4 bits to represent numbers from 0 to 15. So, technically, you could do it with just 4 bits, but if you want to be fancy, you could use 5 bits for a more efficient representation.
18 in binary is 10010 Since 18 can't be written in term of 2 to the power x, the number of bits needed is 5. The answer is 5
A 16-bit file can represent 65,536 different colors. This is achieved by using 16 bits to define the color, typically allocating 5 bits for red, 5 bits for green, and 6 bits for blue, allowing for a wide range of color combinations.
A color image that uses 16 bits to represent a pixel typically divides the bits among the color channels. A common configuration is 5 bits for red, 5 bits for green, and 6 bits for blue (RGB565 format). This allows for a maximum of 65,536 unique colors in the image, as each pixel can represent one of those colors. Thus, the maximum number of distinct colors that a 16-bit image can represent is 65,536.
5 bits are 5 binary digits. If they represent a decimal number, then that number can be anything from zero to 31, and can have either 1 or 2 digits.