Two hex digits represent a single byte. This is because each hex digit corresponds to 4 bits, and since there are 8 bits in a byte, it takes 2 hex digits (4 bits each) to make up 1 byte.
Used for what???The hexadecimal system is just a way to represent information. Each byte requires two hexadecimal digits. Modern computers have billions of bytes in RAM, and often a trillion or more bytes on the hard disk, so that would be billions or trillions of hexadecimal digits. Some examples of things that are often represented as hex digits: * An IPv6 address has 16 bytes - so, 32 hex digits. * A MAC address has 6 bytes (12 hex digits). * A register has a few bytes. The size varies, but is often 2-8 bytes.
Used for what???The hexadecimal system is just a way to represent information. Each byte requires two hexadecimal digits. Modern computers have billions of bytes in RAM, and often a trillion or more bytes on the hard disk, so that would be billions or trillions of hexadecimal digits. Some examples of things that are often represented as hex digits: * An IPv6 address has 16 bytes - so, 32 hex digits. * A MAC address has 6 bytes (12 hex digits). * A register has a few bytes. The size varies, but is often 2-8 bytes.
The largest hex number that can be represented in bytes depends on the number of bytes being considered. Since one byte consists of 8 bits, the maximum value for one byte is 255 in decimal, which is represented as FF in hexadecimal. For multiple bytes, the largest hex number is determined by the number of bytes times 2 (since each byte is represented by two hex characters). For example, for 4 bytes, the largest hex number is FFFFFFFF.
Your question is not very clear, I'm afraid, so I am going to try to guess what you mean... Hex codes are often displayed as pairs of hex (hexadecimal) digits but that is only because two hex digits fit in a byte of data storage. You can only store two hex digits in one byte. There are 16 different hex digits - 0,1,2,3,4,5,6,7,8,9,A,B,C,D,E and F. To store any of those hex digits in binary requires 4 bits, 0 = 0000, 1=0001, 2=0010, 3=0011, ... E=1110 and F=1111. One byte is 8 bits. Therefore, with 8 bits, or one byte, you can only hold two hex digits.
2048
IPv6 address has 2^128 address and IPv6 address is of 16 bytes and is represented in colon hex notation.
2,000,000 Bytes ~ 2 megabytes 2,000,000 B ~ 2 MB
A "hextet" in IPv6 consists of 2 bytes, or 4 hexadecimal digits (as in the example in the question), or 16 bits.
2 bytes= 1 word so, 102400 bytes= 102400/2=51200 words
1kb = 2^10 = 1024 bytes 1 mb = 2^10 = 1024 kb = 2^20 bytes = 1048576 bytes. 22222222 bytes = 21.197 mb 21 mb = 22020096 bytes that is 202126 bytes short of the given no. 202126 bytes = 197.388 kb
There are 4 bytes in 32 bits. (4 * 8 = 32)
2 bytes 8 bits in a byte