2 bytes
8 bits in a byte
2 bytes=16 bits make a word
See the related link. According to that info, you could say about 2048 bytes RAM (it had 1K of 16 bit words, but a byte is 8 bits). And 12K ROM.
there are 1024 words in a 64-bits iterm
A series of 4 bits is called a "nibble." In computing, a nibble can represent 16 different values (from 0 to 15) and is often used in conjunction with bytes, which consist of 8 bits. Nibbles are commonly used in hexadecimal representation, where each nibble corresponds to a single hexadecimal digit.
260 divided by 16 equals 16 with a remainder of 4.
two thousand bits No, there are 8 bits in a byte.
Bytes:32768 Bits:262144
A word. It equals 2 bytes. A Long Word is 32 bits long.
A nibble consists of 4 bits, which is half of a byte (8 bits). Therefore, 1 nibble equals 0.5 bytes. The size of a word can vary depending on the computer architecture, but it is commonly 2 bytes (16 bits) or 4 bytes (32 bits) in many systems.
i dont think there are any. i think its about two different things edit: there are 2: 1 byte = 8 bits
2 bytes=16 bits make a word
2 Bytes(16-bits) make a half word
1 byte = 8 bits By that logic 16 bytes = 8 x 16 bits So 16 bytes contain 128 bits Do note that bits always typically come in powers of two. 2,4,8,16,32,64,128, and so on.
The maximum capacity of a 16-bit memory is 2^16 bits, which equals 65,536 bits. When converted to bytes, this is 65,536 bits divided by 8 bits per byte, resulting in 8,192 bytes or 8 kilobytes (KB). Thus, a 16-bit memory can store a maximum of 8 KB of data.
A 32-bit integer requires 4 bytes of storage (since 32 bits divided by 8 bits per byte equals 4 bytes). A 16-byte cache can therefore store ( \frac{16 \text{ bytes}}{4 \text{ bytes/integer}} = 4 ) 32-bit integers. Thus, a 16-byte cache can hold a total of 4 32-bit integers.
2 bytes because 8-bits is equal to one 1 byte
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