One, rabid.
Three minutes
3 minutes
To kill mice and rats which ate the sailors' food and potentially carried disease.
Well, if 3 cats can kill 3 rats in 3 minutes, that means each cat takes 3 minutes to kill a rat. So, if you have 100 cats and 100 rats, it will still take 3 minutes for all the rats to meet their unfortunate fate. Math doesn't care if you have a cat army or just a trio, it's all about efficiency.
it doesn't matter how many volts pass through your body, its the amps as little as 0.1 amps can kill a human
One lone wolf has the strength of killing a human whenever it attacks it.
It would still take 3 minutes according to the setup of the question, assuming there are enough rats to make this work. It takes 1 cat 3 minutes to find a rat, and 3 minutes for 3 cats to each find a rat. So 100 cats would only take 3 minutes to find 100 rats. Time is irrelevant since the only factors changing are the cats and the rats. However, this question assumes too many things that would likely not happen. The question assumes an even density of rats, that the cat's are equally able to catch rats, and that there are enough rats.
about twelve cases which are dropped directly on the rat
In "Mrs. Frisby and the Rats of NIMH," the rats take the mice with them to start a new community in Thorn Valley, where they can all live together away from human interference. The rats believe that by joining forces with the mice, they can create a stronger and safer community in their new home.
It depends, if you take it with alcohol....
It will take 3 minutes if you look at this problem mathematically. Both scenarios have a ratio of 1 rat to 1 cat. 3 minutes multiplied by 1/1 equals 3 minutes.
10 cats For future reference, this problem is solved as follows: Let C1 be the number of cats who eat O1 rats in T1 minutes and Let C2 be the number of cats who eat O2 rats in T2 minutes C1T1/O1 = C2T2/O2 solve C2 = O2C1T1/O1T2 C2 = 100x5x5/ (5x50) = 10 cats