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What are the default subnet masks for each one of the classes?
The default subnet masks per class are: class A 255.0.0.0 class B 255.255.0.0 class C 255.255.255.0
What is the Maximum number of IP Addressse that can be assigned to hosts on a local subnet that has 255.255.255.224?
32 host per 8 subnet.
How many subnets and hosts per subnet can you get from the network 172.16.0.0?
There are 16 bits available; it is up to you how many of those bits you reserve for the subnet, and how many for the individual hosts within each subnet.
What are necessary procedure in calculating subnet mask or simply subneting show an example forr calculation?
To calculate a subnet mask, first determine the number of subnets needed and the number of hosts per subnet. Use the formula (2^n \geq \text{number of subnets}) for subnetting and (2^h - 2 \geq \text{number of hosts}) for host calculation, where (n) is the number of bits borrowed for subnets and (h) is the number of bits left for hosts. For example, if you start with a Class C address like 192.168.1.0 and want 4 subnets, you would borrow 2 bits (since (2^2 = 4)), resulting in a subnet mask of 255.255.255.192 (or /26), which allows for 62 hosts per subnet.
Will allow 2040 hosts per subnet on the IP network 10.0.0.0?
255.255.248.0
Why does the formula for the number of hosts per subnet 2-2 require the subtraction of two hosts?
one for broadcast i.e 256 and anthoer one is network i.e 0(zero)
Given class C address with a default subnet mask How many possible subnets and usable hosts if 4 bits were borrowed?
that gives you 16 subnets with 14 usable IPs for hosts that is because one is for subnet and one for broadcas in that subnet for example: 192.168.1.0/28 - subnet number 192.168.1.15 -broadcast number usable IPs for hosts - IPs between them that is 14
A company is planning to subnet its network for a maximum of 27 host .which subnet mask would provide the needed hosts and leave the fewest unused addresses in each subnet?
255.255.255.224 would give 32 per subnet or for ex. 192.168.1.1/27 leaving 5 bits or 2-5th power =32
If you have the following Network ID 131.112.0.0 You need at least 500 hosts per network How many networks can you create What subnet mask will you use?
If you need to divide it up into the maximum number of subnets containing at least 500 hosts each, you should use a /23 subnet mask. This will provide you with 128 networks of 510 hosts each. If you used a /24 mask, you would be limited to 254 hosts. Similarly, a /22 mask would be wasteful, allowing you 1022 hosts.
Why you use vlsm?
Variable Length Subnet Mask (VLSM) is the new and efficient way to create Networks as compared to the old Fixed Length subnet mask. In Fixed length subnet masks networks there are 2 categories - the basic is A,B & C subnets and the second is fixed subnets that are created from these basic subnets. But in either of the methods there is lots of IP wastage, as different sections of the network will vary in the number of hosts connected to that network. Wastage is more in the first classic way of networks. It is minimized with the help of subnetting, but the problem still exists as some network segments may contain very less hosts but has to use the same subnet masks as the entire network and thus waste IPs. While when we use VLSM different network segments may contain different subnets as per there requirement and while even doing so they will still be able to interact with each other using routers. The 2 main benefits of VLSM are - 1) Because of different subnet masks the broadcast from one subnet is not transmitted to other subnets. Thus saves lots of bandwidth. 2) It saves lots of IP,which is wasted instead. Hope This helps Happy Networking -- By MyNarutoAnime
As network administrator what is the subnet mask that allows 510 hosts given the IP address?
N - network bitsH - host bitsIf you are following the first octet rule, this is a class B network with a subnet mask of 255.255.0.0 (N.N.H.H). We can subnet this by "borrowing" some bits from the host portion. There are 16 network bits and 16 host bits. There is a simple formula to calculate the proper subnet mask.2 to the power of what equals at least 510(2^X)? We have a total of 16 host bits to borrow from. 2^1...2^2...2^3...Etc2^9= 512 - 2 = 510 host addressesWe subtract two because the network and broadcast address are not usable addresses. As we can see we need at least 9 host bits to get 510 hosts per subnet.Take 32 and subtract it from the host bits you need. So 32-9=23. Your subnet mask now has 23 network bits instead of 16.In binary the original subnet mask would be 11111111.11111111.00000000.00000000.In binary the new subnet mask is 11111111.11111111.11111110.00000000.If you convert this into dotted decimal form you get 255.255.254.0.TLDR: 172.30.0.0 - 172.30.1.255255.255.254.0
Which class of ip addresses offers the most flexibility for subnetting by providing for the largest number of hosts?
A class A would give you the most flexibility in terms of subnets and hosts per subnet. You could use up to 23 bits of information for subnets.
