An valid IP address range can be used on the wireless side of the the routers NAT.
There are 2^24 host in class A but (2^24)-2 hosts are valid since the first and last address are reserved .
class A ip has 16777216 host but valid hosts are only 16777214.(2^24-2)So answer is 16777214 hosts
65,534
256
A classful class B network has a network range of 128 - 191. For host addresses, anything that is legal for an IP address in the last 2 octets would be a valid host address for a class B with no subnets.
254 -- 24 bits of the 32 bit format are fixed (10.0.0 is fixed, so in binary that's 00001010.00000000.00000000) leaving you with the final octet to work with. This octet will yield 256 unique values, but 0 (00000000) and 255 (11111111) are reserved so only 1(00000001) through 254 (11111110) are valid hosts.
"The RFC 1918 private network numbers are 10.0.0.0, Class Bs between 172.16.0.0 and 172.31.0.0 inclusive, and all Class C networks that begin with 192.168. All addresses that begin with 127 are reserved, but not as valid private IP addresses."
No, because the range for class C addresses is 192 - 223, and the first octet of the address 191.76.43.10 is a class B address.
No, 255.255.0.255 is not a valid Class A address. In fact, it is a broadcast address used in Class B networks. Class A addresses range from 1.0.0.0 to 126.255.255.255, and the highest address in this range is 126.255.255.255. Additionally, the address 255.255.255.255 is reserved for the limited broadcast address, not for any specific class.
253. Valid addresses would be from 10.20.50.1 to 10.20.50.254 10.20.50.0 is the network address. 10.20.50.255 is the network broadcast address. Any network with a subnet mask of 255.255.255.0 will support 253 hosts.
Check out this website it has the IP and Subnet mask broken down by subnets and addtional host. http://www.oceanwave.com/technical-resources/network-admin/ip.html 2046 http://www.oceanwave.com/technical-resources/network-admin/ip.html