The highest usable IP address for non-multicast devices is 223.255.255.254 The highest usable multicast IP address is 239.255.255.254
Depends on the subnet. For the subnet of 192.168.1.0, the first usable IP address is 192.168.1.1. This is typical of a default wireless router setup. Valid usable IP addresses under this scenario is 192.168.1.1 to 192.168.1.254.
You mean 192.168.10? The first usable IP in that network would be 192.168.10.1, and ending with 192.168.10.254.
There are 4094 usable IP addresses in a 20-bit subnet.
The number of possible IP address decreases as one steps down from Class A to Class C IP addresses because the availability of usable hosts. There is a decrease in the number of usable hosts from Class A to Class C IP addresses.
172.16.0.0 is itself a private IP address. (IP addresses from 172.16.0.0 to 172. 31.255.255 are all private IP addresses. Other private IP addresses are 10.X.X.X and 192.168.X.X where X can be from 0 to 255). But it's not usable as an IP address for a device such as a PC or host. This is because it's the first address and, by convention, the first address of a network is used to indicate its network address.
typically the router that you are using will take 192.168.1.1. It is a usable address, but it is already taken, so the first IP you can use for a device on that network would be 192.168.1.2 the last usable IP is 192.168.1.254 assuming you are using a subnet mask of 255.255.255.0 Keep in mind that if you are giving devices static IP addresses, it is recommended to reserve the IP address in the DHCP server (typically the router in a home network) or assign it outside of the scope of ip addresses. You can do this through the configuration of the router, typically by entering the router's ip into your browser. (make sure you set your wireless settings to wpa otherwise you will have little or no security)
7
That leaves us 5 bits for the host (32 - 27 = 5); the size of the network is 25 = 32 IP addresses, that is, addresses 10.150.100.96 - 10.150.100.127. The first and last address are not usable (can't be assigned to hosts), which leaves us with addresses 10.150.100.97 - 10.150.100.126.That leaves us 5 bits for the host (32 - 27 = 5); the size of the network is 25 = 32 IP addresses, that is, addresses 10.150.100.96 - 10.150.100.127. The first and last address are not usable (can't be assigned to hosts), which leaves us with addresses 10.150.100.97 - 10.150.100.126.That leaves us 5 bits for the host (32 - 27 = 5); the size of the network is 25 = 32 IP addresses, that is, addresses 10.150.100.96 - 10.150.100.127. The first and last address are not usable (can't be assigned to hosts), which leaves us with addresses 10.150.100.97 - 10.150.100.126.That leaves us 5 bits for the host (32 - 27 = 5); the size of the network is 25 = 32 IP addresses, that is, addresses 10.150.100.96 - 10.150.100.127. The first and last address are not usable (can't be assigned to hosts), which leaves us with addresses 10.150.100.97 - 10.150.100.126.
How many possible host addresses are there in a Class A range?Class A range is 0 - 1270.0.0.0 and 127.0.0.0 are not "routable" IP addresses. One defines all networks and the other is the loopback. We have a total of 126 usable networks and 16,777,214 usable hostaddresses per network.
254
If you aren't subnetting, then the host range for this network would be: 190.254.0.0 - 190.254.255.255 The above shows the IP address range, but not all addresses would be usable (mostly the first and the last addresses would probably be not assignable to a device).