Speed of light in air (which has an index of refraction of 1) is 3 * 10^8 m/s. So divide the speed of light by the index of refraction of the new medium to obtain the speed of light in that medium. Hope I helped!!
The index of refraction, or optical density, is the ratio of the speed of light in a vacuum to that in a given material. Therefore, the index of refraction for this glass is equal to c / v = (3.0 x 10^8 m/s) / (1.6 x 10^8 m/s) = 3.0/1.6 = 1.88
I'll assume that this is the critical angle from the median to a vaccum. You use Snell's law, n1sin(x1) = n2sin(x2) where n1 = index of refraction of your median, n2 = 1 (the index of refraction in a vaccum), x1 = the critical angle (45 degrees), x2 = 90 degrees since light comes out at 90 degrees when it is shone on the critical angle. So... n1sin(45 degrees) = 1 (sin 90 = 1) n1 = 1/sin(45 degrees) n1 = 1.414... Now the index of refraction is the speed of light in a vaccum over the speed of light in the median so: 1.414... = (3.00 x 10^8 m/s) / v v = (3.00 x 10^8 m/s) / 1.414... v= 2.1 x 10^8 m/s
The index of refraction of glass is higher than that of air, meaning light travels slower in glass compared to air. This causes refraction when light passes from air to glass, bending the light rays towards the normal.
The index of refraction of a material is calculated as the speed of light in a vacuum divided by the speed of light in the material. Therefore, if the speed of light in the material is 1.240 x 10^8 m/s, you would divide the speed of light in a vacuum (3.00 x 10^8 m/s) by this value to find the index of refraction.
The index of refraction (n) of a medium can be calculated using the formula ( n = \frac{c}{v} ), where ( c ) is the speed of light in a vacuum (approximately ( 3.00 \times 10^8 ) m/s) and ( v ) is the speed of light in the medium. Given that the speed of light in the solid is ( v = 1.943 \times 10^8 ) m/s, the index of refraction can be calculated as follows: [ n = \frac{3.00 \times 10^8 , \text{m/s}}{1.943 \times 10^8 , \text{m/s}} \approx 1.54. ] Thus, the index of refraction of the solid is approximately 1.54.
my answer is 5
The following assumes you already know the speed of light in a vacuum. You can do measurements related to refraction, applying Snell's law to the angles you measure. This gives you the index of refraction.Once you know the index of refraction, you divide the speed of light in the vacuum by the index of refraction, to obtain the speed of light in water.
Here's the way I see it: Optical reversibility means that if a light passes through a medium with an index of refraction, n, and the light hits that medium at a certain angle, the angle of incidence, the light refracts and comes out at a different angle than the angle of incidence. In other words, if light hits a refracting medium at 10 degrees to the normal, it will refract and come out at 7 degrees to the normal. Then, if it were switched, and the light were made to hit the refracting medium at 7 degrees to the normal, then it would refract and come out at 10 degrees to the normal. This is optical reversibility as seen in refraction. In reflection, however, the angle of incidence and the angle of reflection is the same. If light hits a reflecting medium at 10 degrees, it will reflect at an angle of 10 degrees. So if the angles were switched in this case, it would do nothing, it would just hit the reflecting medium at 10 degrees and again be reflected at 10 degrees. So, does the principle of optical reversibility hold for reflection as well as refraction? It depends on if you view switching the position of the same number to be reversing anything or not. Actually the principle holds good for every optical system in geometric optics....
Refractive index=Sin i divided by Sin r where r= angle of refractioni= angle of incidenceLight rays hitting the boundary at an angle of 23° is refracted at 90° to the normal. Therefore, r= 90 and Sin 90° = 1 . This implies that Refractive index= Sin i=Sin21°= 0.36Speed of light in liquid= Speed of light in air divided by refractive index= 300000000 Divided by 0.36= 833333333.3 m/s
When you look at a pencil in a cup of water and see a distorted image of the pencil it is called "Refraction". I have seen many people post statements saying light is not affected by temperature. This is incorrect. A mirage on the highway is a perfect example. Mirages are caused by hot air near the ground refracting, or bending, light rays upwart into the eyes of a distant observer. Speed of light in a vacuum = 3.00 x 10^8 m/s Refraction of Air at 30oC = 1.00026 Formula: n = c/v v = 3.00 x 10^8 / 1.00026 v = 2.99 x 10^8
The speed of light is a set speed at which all electromagnetic waves travel at in a vacuum. It is 3*10^8 meters/second... That being said, when light, or any other EM wave, travels through a medium it will slow down. Every material has an index of refraction which is the ratio of the speed at which light travels in a vacuum, to the the speed it travels in that material. If you know the index of refraction, you can use Snell's law to determine the speed light will travel through a specific medium. Every medium is different, however a rule of thumb is the denser the medium, the slower light will travel through it. For example, light travels faster in the atmoshpere than it does in water.