3 times
Assume that the increase in length is achieved by uniform reduction in the cross-sectional area of the wire. Then an increase in length by 4 times will result in the cross sectional area being reduced to a fifth of it original value. This will increase the resistance to five times its previous value.
it is tripled
The new volume is 3^3 = 27 times as much.
The volume increases to 33 = 27 times as much.
Actually resistance is directly proportional to the length provided area remains constant. But as we stretch the wire only its volume would remain constant. So its area is to be decreased as length increases. V = pi r^2 * L Now we have R = K * L / pi r^2 Multiplying numerator and denominator by L we get R = K/V * L^2 So resistance is found to be proportional to square of length Hence as length gets increased by 2 times, its resistance value would increase by 4 times.
When the length and width are tripled, the area becomes (3 x 3) = 9 times as much as before.
Cell constant(C) = Resistance(R) X Specific Conductivity(K)
Time period is directly proportional to the square root of the length So as we increase the length four times then period would increase by ./4 times ie 2 times.
There is a direct relationship between the length of wire (thus the number of times the wire is wrapped) and the electrical resistance of the guitar pickup, measured at the two output terminals.
just did this on castle learning the answer is six times
Double the area means half the resistance. Resistance = resistivity times length / area. Resistivity is a property of the material only.
Double the length is double the resistance. Resistance of a wire is the resistivity of the material, times the length, divided by the cross-section area.