There are 59.5 mmols of baking soda and 167 mmols of vinegar. The reaction of the two substances is NaHCO3(s) + CH3COOH(l) = CO2(g) + H2O(l) + Na+(aq) + CH3COO-(aq). This means the limiting reactant is baking soda, and 2.62 grams of CO2 is produced.
22 grams of carbon dioxide contains 12 grams of carbon. This amount of carbon can combine with 32 grams of oxygen to form 44 grams of carbon dioxide.
You need to learn the basics. For starters, you don't work with cups and tablespoons and then switch to grams. Second, vinegar and baking soda react to produce carbon dioxide gas, which bubbles out and goes away, so the answer depends on the strength of the vinegar and when you measure the mass. But if you include the mass of the gas released, the total will be exactly the same as the sum of the masses before you mix them.
To calculate the number of moles of carbon dioxide in 19 grams, divide the given mass by the molar mass of carbon dioxide, which is approximately 44 grams/mol. Therefore, 19 grams of carbon dioxide is equal to 19/44 ≈ 0.43 moles.
What happens is a chemical reaction. Vinagar - acetic acid Baking soda - sodium bicarbonate you are producing sodium acetate with water if you keep adding more vinegar on the baking soda (search "hot ice" on google) note that vinager is not pure but only 5 percent acetic acid the rest is water. for the best fizz use 1200 grams of vineager and 84 grams of NaHCO2 (baking soda) this is one mole of each obviously you can change the proportions. The reason this makes a perfect reaction is because that makes one C2H4O2 molecule react with every NaHCO2 molecule. The bi-products are CO2 H2O and NaC2H2O2
When 42.0 grams of baking soda (sodium bicarbonate, NaHCO3) decomposes, it produces 22.0 grams of sodium carbonate (Na2CO3) and 20.0 grams of carbon dioxide (CO2) gas.
11 grams because all is reacted and there is no reactant left over, although if there were only 3 grams of carbon there would have to be 6 grams of oxygen for this to be viable as carbon dioxide is CO2 so the question asked was itself wrong.
If 12 grams of carbon were used to form the 22 grams of carbon dioxide, this implies that 12 grams of oxygen were consumed in the reaction. Since 20 grams of oxygen were initially available, only 8 grams of oxygen are left unused.
The answer is 99,34 mL carbon dioxide (for a density of CO2 of 1,997 g/L at 0 0C).
To produce 1 mole of urea, 1 mole of carbon dioxide is needed. The molar mass of urea is 60 grams/mol, and the molar mass of carbon dioxide is 44 grams/mol. Therefore, to produce 125 grams of urea, 125 grams/60 grams/mol = 2.08 moles of urea is needed. This means 2.08 moles of carbon dioxide is needed, which is 2.08 moles * 44 grams/mol = 91.52 grams of carbon dioxide needed.
The mass of carbon in carbon dioxide is 12 grams per mole.
A 2-liter bottle of Sprite contains about 5.3 grams of carbon dioxide.
A 12-ounce can of Sprite contains approximately 19 grams of carbon dioxide, which is used to carbonate the beverage.