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To find the number of moles in 5000 grams of calcium, you need to divide the given mass by the molar mass of calcium. The molar mass of calcium is approximately 40.08 g/mol. So, 5000 grams of calcium is equal to 5000/40.08 = 124.69 moles of calcium.
The balanced chemical equation for the reaction between calcium carbonate and aluminum fluoride is: CaCO3 + 2AlF3 -> CaF2 + Al2(CO3)3. To determine the grams of each product produced, you need to first calculate the limiting reactant then use stoichiometry to find the grams of each product formed.
To find the mass in grams of 0.330 mol of calcium, you need to multiply the number of moles by the molar mass of calcium. The molar mass of calcium is approximately 40.08 grams/mol. So, 0.330 mol * 40.08 g/mol = 13.23 grams of calcium.
To calculate the amount of calcium hydride needed to form 4.850 g of hydrogen gas, you need to use the molar ratio between calcium hydride (CaH2) and hydrogen gas (H2), which is 1:2. Therefore, you would need half as many grams of calcium hydride as the grams of hydrogen gas produced, so 2.425 g of calcium hydride would be needed.
To find the number of moles in 28 grams of calcium oxide, we need to divide the given mass by the molar mass of calcium oxide. The molar mass of calcium oxide (CaO) is 56.08 g/mol. So, 28 grams of CaO is equal to 28 g / 56.08 g/mol = 0.5 moles of calcium oxide.
For this you need the atomic mass of Ca. Take the number of grams and divide it by the atomic mass. Multiply by one mole for units to cancel.40.0 grams Ca / (40.08 grams) = .998 moles Ca
To determine the amount of calcium needed, you need to balance the chemical equation for the reaction between calcium and water. The equation is Ca + 2H2O → Ca(OH)2 + H2. Then, convert the mass of water to moles, use the stoichiometry of the balanced equation to find the moles of calcium required, and convert that to grams of calcium.
To find the number of atoms in 187 grams of calcium, we first need to determine the number of moles of calcium. This is done by dividing the mass (in grams) by the molar mass of calcium (40.08 g/mol). Next, we can use Avogadro's number (6.022 x 10^23 atoms/mol) to calculate the number of atoms in that number of moles.
To find the number of atoms in 175 grams of calcium, you first need to calculate the number of moles of calcium using its atomic weight. Then, use Avogadro's number (6.022 x 10^23 atoms per mole) to convert moles to atoms.
To find the number of atoms in 40.08 grams of calcium, you first need to determine the number of moles using the molar mass of calcium (40.08 g/mol). Then, you can use Avogadro's number (6.022 x 10^23 atoms/mol) to calculate the number of atoms. In this case, 40.08 grams of calcium would contain 1 mole of calcium atoms, which is equal to 6.022 x 10^23 atoms.
To make a 0.01 M solution of calcium chloride, you would need to calculate the molecular weight of calcium chloride (CaCl2), which is 110.98 g/mol. Since the molarity is 0.01 M, it means there are 0.01 moles of CaCl2 in 1 liter of solution. Therefore, to make the solution, you would need 1.1098 grams of calcium chloride.
To calculate the number of atoms in 165 grams of calcium, you need to first determine the number of moles using the molar mass of calcium. Calcium has a molar mass of approximately 40.08 g/mol. Once you have the number of moles, you can use Avogadro's number (6.022 x 10^23) to convert moles to atoms.