0.330 moles of calcium has a mass of 13.2 grams.
To find the number of moles in 12.2 grams of calcium, divide the given mass by the molar mass of calcium. The molar mass of calcium is approximately 40.08 g/mol. Dividing 12.2 grams by 40.08 g/mol gives approximately 0.305 moles of calcium.
The molar mass of calcium carbonate (CaCO3) is 100.09 g/mol. Therefore, the mass of 0.5 moles of calcium carbonate would be 0.5 mol x 100.09 g/mol = 50.045 grams.
To find the number of moles in 37 grams of calcium hydroxide, you need to divide the given mass by the molar mass of calcium hydroxide. The molar mass of calcium hydroxide (Ca(OH)2) is 74.1 g/mol. Therefore, 37 grams of calcium hydroxide is equal to 0.499 moles.
The mass of sodium bicarbonate (NaHCO3) is 84 grams/mol, while the mass of calcium carbonate (CaCO3) is 100 grams/mol. Therefore, calcium carbonate has a higher molecular mass compared to sodium bicarbonate.
To find the number of moles in 57.98 grams of calcium, divide the given mass by the molar mass of calcium. The molar mass of calcium is approximately 40.08 g/mol. Therefore, 57.98 g / 40.08 g/mol = approximately 1.45 moles of calcium.
The mass is 0.330 mol Ca (40.08 g/mol) = 13.2 g Ca
To find the number of moles in 12.2 grams of calcium, divide the given mass by the molar mass of calcium. The molar mass of calcium is approximately 40.08 g/mol. Dividing 12.2 grams by 40.08 g/mol gives approximately 0.305 moles of calcium.
The molar mass of calcium carbonate (CaCO3) is 100.09 g/mol. To find the mass of 0.250 mol of calcium carbonate, you would multiply the number of moles by the molar mass: 0.250 mol x 100.09 g/mol = 25.02 grams of calcium carbonate.
To convert moles to grams, you use the molar mass of calcium. The molar mass of calcium is approximately 40.08 g/mol. Therefore, 1.3 moles of calcium would be 1.3 moles x 40.08 g/mol = 52.10 grams of calcium.
The molar mass of calcium carbonate is 100.1 g/mol, and the molar mass of calcium oxide is 56.08 g/mol. Therefore, 12.25 grams of calcium carbonate would produce 6.86 grams of calcium oxide after decomposition.
The molar mass of calcium carbonate (CaCO3) is 100.09 g/mol. Therefore, the mass of 0.5 moles of calcium carbonate would be 0.5 mol x 100.09 g/mol = 50.045 grams.
To find the number of moles in 37 grams of calcium hydroxide, you need to divide the given mass by the molar mass of calcium hydroxide. The molar mass of calcium hydroxide (Ca(OH)2) is 74.1 g/mol. Therefore, 37 grams of calcium hydroxide is equal to 0.499 moles.
For this you need the atomic (molecular) mass of CaCO3. Take the number of moles and multiply it by the atomic mass. Divide by one mole for units to cancel. CaCO3= 100.1 grams2.50 moles CaCO3 × (100.1 grams) = 250.25 grams CaCO3
To find the mass of calcium phosphate (Ca₃(PO₄)₂) in grams for 0.658 moles, first calculate its molar mass. The molar mass of calcium phosphate is approximately 310.18 g/mol. Multiply the number of moles by the molar mass: 0.658 moles × 310.18 g/mol ≈ 204.4 grams. Thus, there are about 204.4 grams of calcium phosphate in 0.658 moles.
To find the number of moles in 5000 grams of calcium, you need to divide the given mass by the molar mass of calcium. The molar mass of calcium is approximately 40.08 g/mol. So, 5000 grams of calcium is equal to 5000/40.08 = 124.69 moles of calcium.
The mass of sodium bicarbonate (NaHCO3) is 84 grams/mol, while the mass of calcium carbonate (CaCO3) is 100 grams/mol. Therefore, calcium carbonate has a higher molecular mass compared to sodium bicarbonate.
To find the number of moles in 28 grams of calcium oxide, we need to divide the given mass by the molar mass of calcium oxide. The molar mass of calcium oxide (CaO) is 56.08 g/mol. So, 28 grams of CaO is equal to 28 g / 56.08 g/mol = 0.5 moles of calcium oxide.